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Ivan
3 years ago
6

The population of the small town of Parks in 2000 was estimated to be 3,901 people with an annual rate of decrease of about 1.8%

. At this rate, what is the estimated population in 2013?
Mathematics
1 answer:
trasher [3.6K]3 years ago
3 0

<u>Answer-</u>

<em>The estimated population in 2013 is </em><em>3081.</em>

<u>Solution-</u>

This can be represented as exponential decreasing function,

y=a(1 - r)^t

Where,

  • a = starting amount
  • r = rate
  • t = years

Putting the values,

y=3901(1 - 0.018)^{13}

=3901(0.982)^{13}

=3901\times 0.7897

=3080.62

As population can not be in fraction, so after rounding off the estimated population in 2013 is 3081.

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Solve the system of linear equations. <br> −8x+5y=26<br> 9x−3y=−3
Sloan [31]

Answer: x = 3 and y = 10

Step-by-step explanation:

-8x + 5y = 26     .................. equation 1

9x - 3y = -3          ................ equation 2

Solving the system of linear equations by elimination method.

The means we have to make the coefficient of one of the variable the same in order to eliminate the variable first.

Let us eliminate the variable y first , this means we will multiply equation 1 by 3 and multiply equation 2 by 5. Doing this , we have

-24x + 15y = 78      ............. equation 3

45x - 15y = -15     ................ equation 4

Now that we have the same coefficient , we have to check their signs , if the have the same signs , we will subtract , that is , if both are having positive signs , we will subtract , if both have negative signs , we will also subtract but if their signs differ we will add. Following this rule and considering the equations above , the coefficients of y have different signs , so we will add equation 3 and equation 4 , so we have:

21x = 63

x = 63/21

x = 3

Substitute x = 3 into equation 1 or equation 2 to get the value of y , using equation 2 , we have

9x - 3y = -3

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Therefore y = 10

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8 0
4 years ago
A car rental agency has 150 cars. The owner finds that at a price of $48 per day, he can rent all the cars. For each $2 increase
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Given that for each <span>$2 increase in price, the demand is less and 4 fewer cars are rented.

Let x be the number of $2 increases in price, then the revenue from renting cars is given by
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Also, given that f</span><span>or each car that is rented, there are routine maintenance costs of $5 per day, then the total cost of renting cars is given by
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Profit is given by revenue - cost.
Thus, the profit from renting cars is given by
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For maximum profit, the differentiation of the profit function equals zero.
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The price of renting a car is given by 48 + 2x = 48 + 2(8) = 48 + 16 = 64.

Therefore, the </span><span>rental charge will maximize profit is $64.</span>
3 0
3 years ago
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