Answer:
D
Step-by-step explanation:
Uhmm mm I think it's true, and so does Siri hahahah
Answer: 
<u>Step-by-step explanation:</u>
Isolate w by performing the following steps
- Multiply by 6 on both sides to clear the denominator
- Subtract 3 from both sides
- Divide both sides by 2
![y=\dfrac{1}{2}+\dfrac{w}{3}\\\\\\6\bigg[y=\dfrac{1}{2}+\dfrac{w}{3}\bigg]\quad \implies \quad 6y=3+2w\\\\\\6y-3=3-3+2w\quad \implies \quad 6y-3=2w\\\\\\\dfrac{6y-3}{2}=\dfrac{2w}{2}\quad \implies \quad \large\boxed{\dfrac{6y-3}{2}=w}](https://tex.z-dn.net/?f=y%3D%5Cdfrac%7B1%7D%7B2%7D%2B%5Cdfrac%7Bw%7D%7B3%7D%5C%5C%5C%5C%5C%5C6%5Cbigg%5By%3D%5Cdfrac%7B1%7D%7B2%7D%2B%5Cdfrac%7Bw%7D%7B3%7D%5Cbigg%5D%5Cquad%20%5Cimplies%20%5Cquad%206y%3D3%2B2w%5C%5C%5C%5C%5C%5C6y-3%3D3-3%2B2w%5Cquad%20%5Cimplies%20%5Cquad%206y-3%3D2w%5C%5C%5C%5C%5C%5C%5Cdfrac%7B6y-3%7D%7B2%7D%3D%5Cdfrac%7B2w%7D%7B2%7D%5Cquad%20%5Cimplies%20%5Cquad%20%5Clarge%5Cboxed%7B%5Cdfrac%7B6y-3%7D%7B2%7D%3Dw%7D)
Answer:
He can buy <u>3 bracelets</u>.
Step-by-step explanation:
Given:
Mr. Gonzales has only 42.50 to spend he wants to buy 29 t shirts including tax and some bracelets that cost 4.50 each including tax.
Now, to find the number of bracelets he can buy.
Let the number of bracelets he can buy be 
Price of each bracelets = 4.50.
Total amount to spend = 42.50.
Number of t-shirts = 29.
Now, to get the number of bracelets we put an equation:

<em>Subtracting both sides by 29 we get:</em>
<em />
<em />
<em>Dividing both sides by 4.50 we get:</em>

<u>The number of bracelets = 3.</u>
Therefore, he can buy 3 bracelets.
Answer:
The graph in the attached figure
see the explanation
Step-by-step explanation:
we have

we know that
The radicand must be greater than or equal to zero
so

solve for x
Adds 3 both sides


Multiply by -1 both sides
Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

so
The domain of the function is the interval (-∞,-3]
For x=-3 ---> the value of y=0
The range is the interval {0,∞)
therefore
The graph in the attached figure