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3 years ago

I need help with is problem.

Mathematics

2 answers:

ad-work [718]3 years ago

8 0

Step-by-step explanation:

A function f(x) can be scaled by a factor of "a" and translated by (h,k) by the relation:

f(x) -> a f(x-h)+k

substitute f(x) by sqrt(x), then

sqrt(x) -> a*sqrt(x-h) + k

So the given equation is derived from f(x) = sqrt(x), hence a radical function.

Dahasolnce [82]3 years ago

6 0

Answer:

d. radical function

Step-by-step explanation:

Moreover, it is rational because of the parent function of y = √x, which can be rewritten as x¹\².

I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.

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Linear equations: w-3=15

motikmotik

Answer:

w = 18

Step-by-step explanation:

w-3=15

Add 3 to each side

w-3+3=15+3

w = 18

6 0

2 years ago

Read 2 more answers

Consider two independent tosses of a fair coin. Let A be the event that the first toss results in heads, let B be the event that

aliina [53]

Answer with Step-by-step explanation:

We are given that two independent tosses of a fair coin.

Sample space={HH,HT,TH,TT}

We have to find that A, B and C are pairwise independent.

According to question

A={HH,HT}

B={HH,TH}

C={TT,HH}

$A\cap B=$ {HH}

$B\cap C$ ={HH}

$A\cap C$ ={HH}

P(E)= $\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}$

Using the formula

Then, we get

Total number of cases=4

Number of favorable cases to event A=2

$P(A)=\frac{2}{4}=\frac{1}{2}$

Number of favorable cases to event B=2

Number of favorable cases to event C=2

$P(B)=\frac{2}{4}=\frac{1}{2}$

$P(C)=\frac{2}{4}=\frac{1}{2}$

If the two events A and B are independent then

$P(A)\cdot P(B)=P(A\cap B)$

$P(A\cap)=\frac{1}{4}$

$P(B\cap C)=\frac{1}{4}$

$P(A\cap C)=\frac{1}{4}$

$P(A)\cdot P(B)=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}$

$P(B)\cdot P(C)=\frac{1}{4}$

$P(A)\cdot P(C)=\frac{1}{4}$

$P(A)\cdot P(B)=P(A\cap B)$

Therefore, A and B are independent

$P(B)\cdot P(C)=P(B\cap C)$

Therefore, B and C are independent

$P(A\cap C)=P(A)\cdot P(C)$

Therefore, A and C are independent.

Hence, A, B and C are pairwise independent.

6 0

2 years ago

Choose the correct simplification of the expression 9 over h to the power of negative 3

Vitek1552 [10]

Remove the negative exponent by rewriting x^-3 as 1/x^3
(9)/(1/x^3)
multiply the numerator by the reciprocal of the denominator
9x^3

8 0

3 years ago

Read 2 more answers

You are standing above the point (5,5)(5,5) on the surface z=15−(2x2+2y2)z=15−(2x2+2y2). (a) in which direction should you walk

Marianna [84]

Since the surface is the top part of a sphere centred on the origin, the directions of steepest descent are any vector originating from the origin (0,0).

At (5,5), the direction would be dictated by the line joining (5,5) and the origin (0,0), i.e. along <5,5> or equivalently along <1,1>.

You can also go through vector calculus to arrive at the same result.

6 0

3 years ago

Expanded form for 13 cubed

saw5 [17]

The answer to this question is 2197! Hope this helped :3

5 0

3 years ago

I need help with is problem.​

I need help with is problem.