Answer:
Time,t that it will elapse before the concerntration of the dye in the tank reaches1% of its original value is 460.52 seconds
Step-by-step explanation:
Let Q(t) = amount of dye for all time,t.
Let Q'= rate in - rate out.
But Q/200 = concerntration of dye
Therefore rate out= Q/200 ×2.
Q'/Q = - 1/100
Dividing by Q gives
Ln/Q/ + c = -1/100t + c1
Integrating both sides with respect to t
Ln/Q/ = -1/100t + c2.
c1 and c1 are just another constants
Q= c3e^-t/100
Exponentiating both sides will cause the absolute values to get absorbed into the constants giving rise to a new constant c3
200= c3-0/100
c3= 200
2= 200e^-t/100
Ln1/100= - t/100
Ln0.01 = - t/ 100
Cross multiply
t= Ln0.01 × 100
t = 4.6052 ×100
t = 460.52seconds
You would set up a proportion for people that choose beach/ total
So (14+17+19)/(50+50+50) which simplifies to 50/150 or 1/3
From here we can set 1/3 = x/1200 and solve for x
To do this we would multiply each side by 1200 to isolate x
(1/3)×1200= 400
So x=400
Therefore, 400 people can be expected to pick the beach
If this is i-ready it shouldn’t be difficult nor should you be using Brainly if it’s a diagnostic or something.
Answer:
40/3
Step-by-step explanation:
w = weight of soil needed
f = number of flower beds
a = constant value
w = a * f
<em>substitute</em>
10 = 6a
<em>simplify</em>
5/3 = a
w = (5/3)f
<em>plug in 8</em>
w = (5/3)(8)
<em>simplify</em>
w = 40/3
