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Shalnov [3]
3 years ago
8

Drag each title to the correct box. Not all tiles will be used

Mathematics
1 answer:
mestny [16]3 years ago
5 0

Answer:

4, 1, 6.

See explanation

Step-by-step explanation:

You are given the equation

d=vt-\dfrac{1}{2}at^2

First subtract vt from both sides:

d-vt--\dfrac{1}{2}at^2

and multiply the equation by -1:

vt-d=\dfrac{1}{2}at^2\ \ \ \ (1)

Now multiply (1) by 2:

2(vt-d)=at^2\ \ \ \ \ (2)

At last, divide by a

t^2=\dfrac{2(vt-d)}{a}\ \ \ \ \ (3)

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Answer:

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Step-by-step explanation:

The two expressions are only said to be equivalent if they are the same regardless of whatever value the variable(s) is.

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To prove this, we equate both expressions:

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