Evaluate 3(a – 4b) when a = –2 and b = 5.<br> a. 54<br> b. 39<br> c. –54<br> d.

Which of the following tables represents exponential functions?

HACTEHA [7]

The 2 graphs on the left are exponential
The other 2 are linear

5 0

3 years ago

Information collected from runner 3# is in the table below

Shtirlitz [24]

Answer:

the constant of proportionality would be 9

5 0

2 years ago

Matthew has a 150 page book he has read one third of it how many pages has he read so far

posledela

You take 150/3. The answer is 50.

8 0

3 years ago

The lengths of pregnancies in a small rural village are normally distributed with a mean of 265 days and a standard deviation of

MakcuM [25]

Answer:

the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days

Step-by-step explanation:

Given that :

Mean = 265

standard deviation = 14

The formula for calculating the z score is $z = \dfrac{x -\mu}{\sigma}$

x = μ + σz

At middle of 50% i.e 0.50

The critical value for $z_{\alpha/2} = z_{0.50/2}$

From standard normal table

$z_{0.25}=$ + 0.67 or -0.67

So; when z = -0.67

x = μ + σz

x = 265 + 14(-0.67)

x = 265 -9.38

x = 255.62

when z = +0.67

x = μ + σz

x = 265 + 14 (0.67)

x = 265 + 9.38

x = 274.38

the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days

3 0

3 years ago

Mr jones is planning to pant grass and place afence in a small area for his dog. The rectagular dimension are 12×15 feet. The gr

goldenfox [79]

Answer:

A) The total feet needed for the fence total perimeter is 54 feet

B) The total cost of fence is $432

C) The square feet of grass needed foe the total area is 180 square feet

D) The total cost of the project is $572

Step-by-step explanation:

Given as :

The dimension of rectangular field

Length of rectangular field = L = 12 feet

width of rectangular field = w = 15 feet

The cost of grass per square foot = 50 cents = $0.5 ( ∵ 1 cents = $0.01 )

The cost of small fence = $8 per linear foot

Now, According to question

A ) Let The total feet needed for the fence total perimeter = A feet

∵ Perimeter of rectangular field = 2 × Length + 2 × width

Or, A = 2 × L + 2 × w

Or, A = 2 × 12 feet + 2 × 15 feet

Or, A = 24 feet + 30 feet

∴ A = 54 feet

So, The total feet needed for the fence total perimeter = A = 54 feet

B ) Let The total cost of fence = $B

So, The total cost of fence = The cost of small fence × perimeter of fence

i.e B = $8 × 54 feet

∴ B = $432

So,The total cost of fence = B = $432

C) Let the square feet of grass needed foe the total area = C square feet

∵The Area of rectangular fence = Length × width

Or, The square feet of grass needed foe the total area = Area of rectangular fence = L × w

i.e C = 12 feet × 15 feet

Or, C = 180 feet²

So,The square feet of grass needed foe the total area = C = 180 square feet

D) Let The total cost of grass = $D

∵ The cost of grass per square foot = $0.5

So,Total cost of grass = $0.5 × Area of fence

i.e D = $0.5 × 180 feet²

Or, D = $90

So, The Total cost of grass = D = $90

E) Let the total cost of the project = $E

∵Mr. Jones spend additional $50 for tools

So, The total cost of the project = money spent on tools + total cost of fence + Total cost of grass

i.e E = $50 + B + D

Or, E = $50 + $432 + $90

∴ E = $572

So, The total cost of the project = E = $572

Hence,

A) The total feet needed for the fence total perimeter is 54 feet

B) The total cost of fence is $432

C) The square feet of grass needed foe the total area is 180 square feet

D) The total cost of the project is $572 Answer

3 0

3 years ago

Evaluate 3(a – 4b) when a = –2 and b = 5. a. 54 b. 39 c. –54 d. –66