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3 years ago

Can someone answer this ASAP? NO IMAGE EXAMPLES PLEASE I CANT SEE THEM

Mathematics

2 answers:

Arturiano [62]3 years ago

4 0

Answer is 6.3 because the area of the triangle is 40 but then when you do it by it’s square roots it becomes 6.3

kkurt [141]3 years ago

3 0

Answer:

Step-by-step explanation:

Given, 

Area of a triangle = 40

Therefore, 

Side of the square

$= \sqrt{40}$

= 6.3245553203

= 6.3 (estimated) (Ans)

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Which scales are equivalent to 1 inch to 1 foot?

Radda [10]

Answer:

A, B, D, F

Step-by-step explanation:

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3 years ago

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Please help finding area

Vikki [24]

Answer:

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3 years ago

Find angle x,y,x,p! 'very easy

MArishka [77]

Answer:

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Step-by-step explanation:

y=120

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3 years ago

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What is the positive slope of the asymptote of (y+11)^2/100-(x-6)^2/4=1? The positive slope of the asymptote is .

VladimirAG [237]

Answer:

the positive slope of the asymptote = 5

Step-by-step explanation:

Given that:

$\frac{(y+11)^2}{100} -\frac{(x-6)^2}{4} =1$

Using the standard form of the equation:

$\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}= 1$

where:

(h,k) are the center of the hyperbola.

and the y term is in front of the x term indicating that the hyperbola opens up and down.

a = distance that indicates how far above and below of the center the vertices of the hyperbola are.

For the above standard equation; the equation for the asymptote is:

$y = \pm \frac{a}{b} (x-h)+k$

where;

$\frac{a}{b}$ is the slope

From above;

(h,k) = 11, 100

$a^2$ = 100

a = $\sqrt{100}$

a = 10

$b^2 =4$

b = $\sqrt{4}$

b = 2

$y = \pm \frac{10}{2} (x-11)+2$

$y = \pm 5 (x-11)+2$

y = 5x-53 , -5x -57

Since we are to find the positive slope of the asymptote: we have

$\frac{a}{b}$ to be the slope in the equation $y = \pm \frac{10}{2} (y-11)+2$

$\frac{a}{b}$ = $\frac{10}{2}$

$\frac{a}{b}$ = 5

Thus, the positive slope of the asymptote = 5

8 0

2 years ago

A robin perched in a tree 40 feet above sea level. Directly below the robin, a seagull is flying 13 feet above sea level. Direct

katrin [286]

Answer:

See explanation

Step-by-step explanation:

The question is incomplete. However, I'll solve on a general terms.

Since the robin, seagull and fish are on directly below one another; a possible question could be to calculate the distance between the robin and the clownfish

The given parameters are:

$Robin = +40ft$

$Seagull= +13ft$

$Clownfish= -33ft$

+ represents above sea level while i represents below

The distance is then calculated as:

$Distance = Robin - Clownfish$

$Distance = +40ft - (-33ft)$

$Distance = +40ft +33ft$

$Distance = 73\ ft$

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3 years ago