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3 years ago

84 is what percent of 105?

Mathematics

2 answers:

Reptile [31]3 years ago

8 0

Answer:

The answer is 80 percent

saul85 [17]3 years ago

3 0

Answer:

80%

Step-by-step explanation:

84/105=0.8

0.8=80%

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What is the square root of 144?

choli [55]

Answer:

$12$

Step-by-step explanation:

$\sqrt{144 } = \sqrt{12 \times 12} = 12$

6 0

3 years ago

Read 2 more answers

How long would it take you to double your money is the bank pays 3.6% interest, compounded

Lapatulllka [165]

Answer:

$t=19.25\ years$

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$t=?\ years\\P=x\\r=3.6\%=3.6/100=0.036\\A=2x$

substitute in the formula above

$2x=x(e)^{0.036t}$

solve for t

simplify

$2=(e)^{0.036t}$

Apply ln both sides

$ln(2)=ln[(e)^{0.036t}]$

Applying property of exponents

$ln(2)=[0.036t]ln(e)$

Remember that ln(e) =1

$ln(2)=[0.036t]$

$t=ln(2)/[0.036]$

$t=19.25\ years$

7 0

3 years ago

Zander read 13 3/4pages in 1/4 of an hour. Sydney read 43 1/3 pages in 2/3 of an hour. At these rates, would Zander or Sydney re

kakasveta [241]

Answer:

At these rates Sydney read 10 pages per hour more than Zander.

Step-by-step explanation:

Zander read $13\frac{3}{4}$ pages in $\frac{1}{4}$ of an hour.

Therefore, pages read by Zander in 1 hour = $\frac{\text{Total pages read}}{\text{Total time taken}}$

= $\frac{13\frac{3}{4}}{\frac{1}{4}}$

= $\frac{55}{4}\times \frac{4}{1}$

= 55 pages per hour

Sydney read $43\frac{1}{3}$ pages in $\frac{2}{3}$ of an hours.

Pages read by Sydney in 1 hour = $\frac{43\frac{1}{3}}{\frac{2}{3} }$

= $\frac{130}{3}\times \frac{3}{2}$

= 65 pages per hour

Therefore, number of pages read more by Sydney as compared to Zander,

= 65 - 55

= 10 pages per hour

At these rates Sydney read 10 pages per hour more than Zander.

4 0

2 years ago

HI could some one pleaseeee HELP ME !!!

Ksivusya [100]

Answer:

The answer is 48

Step-by-step explanation:

Substrac 180-132 and that's the answer

5 0

3 years ago

Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 3.0 km/h due east. Runner B is initia

ArbitrLikvidat [17]

Answer:

The distance of the two runners from the flagpole is 0.0882 km

Step-by-step explanation:

We are going to use the minus sign when the runner is on the west and the plus sign when the runner is on the east.

Then, Taking into account the runner A is 6 km west and is running with a constant velocity of 3 Km/h east, the distance of the runner A from the flagpole is given by the following equation:

Xa = -6 Km + (3 Km/h)* t

Where Xa is the position of the runner A from the flagpole and t is the time in hours.

At the same way the distance of the runner B, Xb, from the flagpole is given by the following equation:

Xb = 7.4 Km - (3.8 Km/h)*t

Then, the two runners cross their path when Xa is equal to Xb, so if we solve this equation for t, we get:

Xa = Xb

-6 + (3*t) = 7.4 - (3.8*t)

(3.8*t) + (3*t) = 7.4 + 6

(6.8*t) = 13.4

t = 13.4/6.8

t = 1.9706

Therefore, at time t equal to 1.9706 hours, both runners cross their path. The distance of the two runners from the flagpole can be calculated replacing the value of t in equation for Xa or in equation for Xb as:

Xa = -6 Km + (3 Km/h)* t

Xa = -6 Km + (3 Km/h)*(1.9706 h)

Xa = -0.0882 Km

That means that both runners are 0.0882 Km west of a flagpole.

4 0

3 years ago