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3 years ago

If the discriminate of a quadriatic equation is 4, how many solutions does the equation have?

Mathematics

1 answer:

Tanya [424]3 years ago

5 0

Answer:

two solutions

Step-by-step explanation:

If you have a discriminant value greater than zero (not zero and not negative), you're gonna have two solutions. For zero discriminant, one solution. For negative discriminant, no solutions at all.

Make sure you remember this. It will save you from solving a quadratic equation which has no solutions.

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Tems11 [23]

Answer:

168

Step-by-step explanation:

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You can then multiply the original height by 12 to get the answer

12 X 14 =168

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2 years ago

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The answer would be B

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Suppose Bob borrows $5,000 for three years from his rich uncle, who agrees to charge Bob simple interest at 5% annually. How muc

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2 years ago

35 hundreds = 5 tens times 7 tens is it true or false

Strike441 [17]

True
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3 0

3 years ago

Assume lim f(x)-6 and lim g(x)-9. Compute the following limit and state the limit laws used to justify the computation.

emmasim [6.3K]

Answer:

Step-by-step explanation:

<h3><u>some relevant limit laws</u></h3>

lim C = C where c is a constant.

lim( f(x) + g(x)) =lim f(x) + lim g(x)

lim( f(x)g(x)) =lim f(x) * lim g(x)

lim( cg(x)) =clim g(x)

lim( f(x)/g(x)) =lim f(x) / lim g(x) if lim g(x) is not equal to zero.

lim( f(x))^2 = (lim f(x) )^2

lim square root( f(x)) = square root(lim f(x) )

$\lim_{n \to 3} g(x) = 9\\\\\lim_{n \to 3} f(x) = 6\\\\ \lim_{n \to 3} \sqrt[3]{f(x)g(x) + 10} \\\\ = \lim_{n \to 3} \sqrt[3]{f(x)g(x) + 10}\\\\= \sqrt[3]{lim_{n \to 3}f(x) \times lim_{n \to 3}g(x) + 10}\\\\= \sqrt[3]{6 \times 9 + 10}\\\\= \sqrt[3]{64}$

= 4

4 0

3 years ago