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DedPeter [7]
3 years ago
10

How do you do this?

Mathematics
1 answer:
masya89 [10]3 years ago
5 0
Remeber y=mx+b that can be useful n get everything on other side of = but y

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Find any intercepts for the graph of x divided by a y divided b=1 the x-intercept is
Nimfa-mama [501]
Hello,

(x/ay)/b =1==>bx=ay==>y=b/a*x

If y=0 then x=0
x-intercept is 0

3 0
3 years ago
(Geometry Question) <br> For Tangent A, would it be 1.05 or 0.9524?
ohaa [14]

Answer :

tan(A) = 1.05

Explanation in the above picture

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3 years ago
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Show each step of your work. <br><br> Solve -3x + 12 = x – 4.
kodGreya [7K]

Answer:

x=4

Step-by-step explanation:

-3x+12-12=x-4-12

-3x=x-16

-3x-x=x-16-x

-4x=-16

-4 divided by -16

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3 years ago
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if the rits car is going 69mph and his destination is 4 hours and 20 minutes away how long will it take for the rits car to get
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3 0
4 years ago
Show that cos(3theta) = 4cos3(theta) − 3cos (theta).
Delvig [45]

<u>Step-by-step explanation:</u>

To prove:

\cos 3\theta=3\cos^3 \theta-3\sin^2 \theta\cos \theta

Identities used:

\cos(A+B)=\cos A\cos B+\sin A\sin B      ......(1)

\sin 2A=2\sin A\cos A        ........(2)

\cos 2A=\cos^2A-\sin^2 A    .......(3)

\sin^2A+\cos^2A=1       .......(4)

Taking the LHS:

\Rightarrow \cos 3\theta=\cos (\theta +2\theta )

Using identity 1:

\Rightarrow \cos (\theta +2\theta )=\cos \theta \cos 2\theta-\sin \theta \sin 2\theta

Using identities 2 and 3:

\Rightarrow \cos \theta (\cos ^2\theta-\sin^2 \theta )-\sin \theta (2\sin \theta \cos \theta )\\\\\Rightarrow \cos^3\theta -\sin^2\theta \cos \theta -2\sin^2 \theta \cos \theta \\\\\Rightarrow \cos^3\theta -3\sin^2\theta \cos \theta

Using identity 4:

\Rightarrow \cos^3\theta -3(1-\cos^2\theta) \cos \theta\\\\\Rightarrow \cos^3\theta-3\cos \theta+3\cos^3\theta\\\\\Rightarrow 4\cos^3\theta -3\cos \theta

As, LHS = RHS

Hence proved

5 0
3 years ago
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