Since ABCD is a square
BE = FD
BC = AB
Angle ABE = angle BCF
With these, triangle ABE = triangle BCF
And
angle BEA = angle CFB by CPCTC
And with this
DG = AB
Y = tan (x)
Y = 3x0.8x + 6
(0,0) (0,9)
Answer:
D. HL (hypotenuse leg)
Step-by-step explanation:
There are two triangles in the picture, ABQ and CDP. The condition for the hypotenuse leg are:
1. both triangles are right triangle
2. the hypotenuse and one of the leg/side is equal
Both B and D angle is 90 degrees, so both triangles is right triangle. The hypotenuse for the triangle is AQ and PC, and both are equal. One of the triangles legs also equal, which is AB and CD. With that, you fulfill HL postulate for the congruent triangle.
Don't confuse this with SAS theorem for the same angle should be on the middle of two equal sides.
120x.04 =4.8
Add to original 120
Final answer $124.80
Answer:
At a combined speed of 6 in/min, it takes us 24 mins to clean the wall
Step-by-step explanation:
Since the question did not provide the speed with which each student cleans, we can make assumptions. This is so that we can solve the question before us
Assuming student 1 cleans at a speed of 2 inches per minute, student 2 cleans at a speed of 2½ inches per minute & student 3 cleans at a speed of 1½ inches per minute.
Let's list the parameters we have:
Height of wall (h) = 12 ft, Speed (student 1) = 2 in/min, Speed (student 2) = 2½ in/min, Speed (student 3) = 1½ in/min
Speed of cleaning wall = Height of wall ÷ Time to clean wall
Time to clean wall (t) = Height of wall ÷ Speed of cleaning wall
since students 1, 2 and 3 are working together, we will add their speed together; v = (2 + 2½ + 1½) = 6 in/min
1 ft = 12 in
Time (t) = h ÷ v = (12 * 12) ÷ 6 = 144 ÷ 6
Time (t) = 24 mins
