4:11 ratio 1:n
To find n, we have to make the left hand sides the same. I suggest that dividing the first one by four will give us one. We have to treat both sides the same, so we divide the 11 by 4 as well, and that gives us the answer.
1 : 2.75.
Answer:
a. The proportion of vehicle speeds were between 25 and 57 mph is 68.26%
b.The proportion of vehicle speeds exceeded 57 mph is 15.87%.
Step-by-step explanation:
a. To calculate what proportion of vehicle speeds were between 25 and 57 mph we would have to make the following calculations:
Probability that the vehicle speeds were between 25 and 57 mph is given by:
P(25≤x≤57)
=P(<u>25-41 </u>≤ <u>x-μ </u> ≤ <u>57-41)</u>
16 σ 16
=P(-1≤z≤1)
=P(z≤1)-P(z≤1)
=0.8413-0.1587
=0.6826
The proportion of vehicle speeds were between 25 and 57 mph is 68.26%
b. To calcuate what proportion of vehicle speeds exceeded 57 mph, we would have to make the following calculation:
Probability that vehicle speeds exceeded 57 mph is given by
P(x>57)
=P(<u>x-μ </u> > <u>57-41)</u>
σ 16
=P(z>1)
=1-P(z≤1)
=1-0.8413
=0.1587
The proportion of vehicle speeds exceeded 57 mph is 15.87%.
I’m sorry but I don’t understand this
If she is setting up a proportion to find the percent, the value of m would be any variable and the value of n would be 100. When she solves the problem, m=65%.
13/20 is part out of whole. The rest of the proportion will be "percent out of 100"; since we don't initially know the percent, we use a variable. Thus we have
13/20 = m/100
Cross multiply:
20*x = 13*100
20x = 1300
Divide both sides by 20:
20x/20 = 1300/20
x = 65
Answer:
200+2w>400 and w>100.
Step-by-step explanation:
The perimeter of a rectangle can be found using 2*l + 2*w = P. If the length is 100 cm then 2(100)+2w > 400. Simplified this is 200+2w>400.
You can solve for the width and you find
200+2w>400
2w>200
w>100.
