All categories

3 years ago

I don’t get this at all help.?

Mathematics

1 answer:

Karolina [17]3 years ago

4 0

Answer:

Step-by-step explanation:

a) Volume of prism: 6 units x 4 units x 7 units = 168 cubic units

b) Area of shaded base: 4 units x 7 units = 28 square units

Volume of prism: 6 x 4 x 7

You might be interested in

4 1/8 take away 2 3/4

Rudiy27

Answer:

1.375

Step-by-step explanation:

6 0

3 years ago

Jose's school spent $1284 on 9 sticksof memory and a new hard drive. The hard drive cost $168. Which is the reasonable estimate

myrzilka [38]

Subtract the cost of the hard drive from the original $1284 and divide the answer you got by the 9 sticks of memory for your answer.

4 0

4 years ago

Read 2 more answers

The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in

Anon25 [30]

We have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is $[2,\infty)$ .

If we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

Let us know find its inverse.

$y=(x-5)^{2}+2$

Upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

Let us now solve this function for y.

$(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\$

Hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .

8 0

3 years ago

Rewrite the following radical term into rational exponent form. √x

bixtya [17]

Answer:

x¹/²

Step-by-step explanation:

Taking the square root of a number is the same as taking it to the power of one half.

3 0

3 years ago

Change 1 hour 25 minutes 29 seconds to seconds

Orlov [11]

Answer:

remember

1h=60min

1min=60 sec

now come to the question

1h=60min

1min=60 sec

60min=60×60=3600sec in 1hour

25min=60×25=1500sec in 25 min

total all sec=3600+1500+29=5129sec

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers