Answer:
10 and 12
Step-by-step explanation:
let the consecutive even integers be n and n + 2 , then
n² - 64 = 3(n + 2) ← distribute parenthesis
n² - 64 = 3n + 6 ( subtract 3n + 6 from both sides )
n² - 3n - 70 = 0 ← in standard form
(n - 10)(n + 7) = 0 ← in factored form
Equate each factor to zero and solve for n
n - 10 = 0 ⇒ n = 10
n + 7 = 0 ⇒ n = - 7
Since n must be a positive even integer then n = 10 and n + 2 = 10 + 2 = 12
The 2 numbers are 10 and 12
ANSWER
No solution
EXPLANATION
The first equation is
and the second equation is
We equate the two equations to obtain;
This implies that
There is no real number whose square is -1.
Therefore, the equation has no solution.
the last two ones be the same, the outcomes would be TTT,HTT,THH,HHH
so the probability is 4/8 = 1/2.
Answer:
-6
Step-by-step explanation:
r = 9, b = 5, g = -6
Plug these values into (r + b - 8)(b + g)
[(9) + (5) - 8]*[(5) + (-6)]
Combine like terms in the brackets
[6]*[-1]
6 times -1 equals -6, so that is your answer
