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NikAS [45]
2 years ago
8

2x × 9 = ? What is the answer? Is the answer 18x?

Mathematics
2 answers:
notsponge [240]2 years ago
8 0

Answe18x

Step-by-step explanation:

2x9 is 18, and you just add the x

scoundrel [369]2 years ago
5 0

Answer:

The answer is 18x.

Step-by-step explanation:

2x times 9 is 18x because when you multiply 9 times 2, you get 18 and the x carries over.


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2 years ago
Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane
liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

Answer:

Rate = 0.935042^\circ /cm

Step-by-step explanation:

Given

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

T(x,y) =x\sin2y

r = 1m

v = 2m/s

Express the given point P as a unit tangent vector:

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

u = \frac{\sqrt 3}{2}i - \frac{1}{2}j

Next, find the gradient of P and T using: \triangle T = \nabla T * u

Where

\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})}  = (sin \sqrt 3)i + (cos \sqrt 3)j

So: the gradient becomes:

\triangle T = \nabla T * u

\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] *  [\frac{\sqrt 3}{2}i - \frac{1}{2}j]

By vector multiplication, we have:

\triangle T = (sin \sqrt 3)*  \frac{\sqrt 3}{2} - (cos \sqrt 3)  \frac{1}{2}

\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)

\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5

\triangle T = 0.935042

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Rate = \triangle T = 0.935042^\circ /cm

3 0
2 years ago
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notsponge [240]

Answer:

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IgorC [24]

<h3><u>Given</u><u> </u><u>points</u><u>:</u><u>-</u></h3>
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We know that

{\boxed{\sf Slope_{(m)}=\dfrac {y_2-y_1}{x_2-x_1}}}

  • Substitute the values

\qquad\quad {:}\longrightarrow\tt m=\dfrac {3-2}{7-0}

\qquad\quad {:}\longrightarrow\tt m=\dfrac {1}{7}

\therefore \sf Slope\:of\:the\:line\:is\:\dfrac {1}{7}

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Luden [163]

Answer:

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Step-by-step explanation:

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