By comparing the given shape with easier ones like triangles and rectangles we will see that the area of the shape is 8 square units.
<h3>
How to simplify the shape.</h3>
So the given shape is a little bit complex, but you can actually see that it is a triangle with a base of 8 units with a height of 4 units, where a rectangle of 2 in by 3 in was removed, and also removed a triangle of height of 2 inches and base of 2 inches.
Remember that:
- A triangle of height H and base B has an area = B*H/2
- A rectangle of length L and width W has an area = L*W.
Then the area of the given shape is:
A = 8*4/2 - 3*2 - 2*2/2
A = 16 - 6 - 2
A = 8
So the given shape has an area of 8 square units.
If you want to learn more about areas, you can read:
brainly.com/question/14137384
answer: -5x+12=20
-12 -12
-5x/-5= 8/-5
x= -1.6
Check: rewrite the orignal problem
plug your variable
Answer:
The answer is 160
Step-by-step explanation:
Comment
There really should be no answer to this. It sort of destroys the meaning of equality. However, you might be working in different bases. I'll assume that, but the base will be a fraction, which brings up other problems.
Solution
You have 5 17s there. So you will need five 32s. 5 * 32 = 160
The answer is 160
Answer:
1) 
2) 12 inches tall.
Step-by-step explanation:
1) The equation of the line in Slope-Intercept form is:
Where "m" is the slope and "b" is the y-intercept.
In this case:
(The height of the candle in inches)
(The time in hours)
Then, we can rewrite it:
Based on the information provided in the exercise, the line passes through these points:
and 
Then, we can find the slope of the line with the formula 
:
Now we need to substitute the slope and one of the points into and then solve for "b":
Substituting values, we get that the a linear equation that models the relationship between the heigth of the candle and the time, is:
2) We must substitute 
into the linear equation in order to find the height of the candle after burning 8 hours:
Answer:
27
Step-by-step explanation:
Evaluate the ![\sqrt[4]{81}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B81%7D)
= 3
Since 
= 81
We are noe left to evaluate (3)³ = 27
