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DedPeter [7]
3 years ago
8

Limit of x^2-81/x+9 As x goes toward -9

Mathematics
1 answer:
Semmy [17]3 years ago
7 0
Hello,

Use the factoration

a^2 - b^2 = (a - b)(a + b)

Then,

x^2 - 81 = x^2 - 9^2

x^2 - 9^2 = ( x - 9).(x + 9)

Then,

Lim (x^2- 81) /(x+9)

= Lim (x -9)(x+9)/(x+9)

Simplity x + 9

Lim (x -9)

Now replace x = -9

Lim ( -9 -9)

Lim -18 = -18
_______________

The second method without using factorization would be to calculate the limit by the hospital rule.

Lim f(x)/g(x) = lim f(x)'/g(x)'

Where,

f(x)' and g(x)' are the derivates.

Let f(x) = x^2 -81

f(x)' = 2x + 0
f(x)' = 2x

Let g(x) = x +9

g(x)' = 1 + 0
g(x)' = 1

Then the Lim stay:

Lim (x^2 -81)/(x+9) = Lim 2x /1

Now replace x = -9

Lim 2×-9 = Lim -18

= -18




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Answer:

y = 4/5x + 3/5  

Step-by-step explanation:

In the slope-intercept form, y = mx + b, we need to find the values of the slope (m) and the y-intercept.

Using points (-7, -5) and (3, 3), we can calculate for the slope of the equation given the formula:

m = \frac{y2 - y1}{x2 - x1}

Let (x1, y1) = (-7, -5)

and (x2, y2) = (3, 3).

Plug the given values into the slope formula:

m = \frac{y2 - y1}{x2 - x1} = \frac{3 - (-5)}{3 - (-7)} = \frac{3 + 5}{3 + 7} = \frac{8}{10} = \frac{4}{5}

Therefore, the slope of the line is 4/5.  

Next, we need to find out the value of the y-intercept (b).

We can use one of the given points, (3, 3), along with the slope (4/5) to solve for the y-intercept:

y = mx + b

3 = 4/5(3) + b

3 = 12/5 + b

Subtract 12/5 from both sides:

3 - 12/5 = 12/5 - 12/5 + b

3/5 (or 0.6) = b

Therefore, the y-intercept is 3/5.

We can now establish our linear equation as:

y = 4/5x + 3/5

Please mark my answers as the Brainliest if you find this solution helpful :)  

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