<span>An attribute in a relation of a database that serves as the primary key of another relation in the same database is called a</span>
Answer:
hello please join the
Explanation:
you should join the green alien squad in gta
Answer:
Written in Python
import math
principal = 8000
rate = 0.025
for i in range(1, 11):
amount = principal + principal * rate
principal = amount
print("Year "+str(i)+": "+str(round(amount,2)))
Explanation:
This line imports math library
import math
This line initializes principal amount to 8000
principal = 8000
This line initializes rate to 0.025
rate = 0.025
The following is an iteration from year 1 to 10
for i in range(1, 11):
This calculates the amount at the end of the year
amount = principal + principal * rate
This calculates the amount at the beginning of the next year
principal = amount
This prints the calculated amount
print("Year "+str(i)+": "+str(round(amount,2)))
Answer:
An advantage to Corporations aI's a business organization is that they enjoy unlimited life and limited liability.
Explanation:
Unlimited life and limited liability are the major advantages of corporations.
Corporations have unlimited life unless all the shareholders decides to dissolve the corporation.
It has limited liability, it means that only the company assets will be sold in case of debt and investors are not liable to pay the debt.
Answer:
The longest codeword that could possibly be for "n" symbol is n-1 bits.
Explanation:
From the given information:
Suppose we are to consider a set of frequencies
, for which f is a symbol for the length n. Therefore, the longest codeword that could possibly be for "n" symbol is n-1 bits.
However, during the encoding for "n" in conjunction with n-2, then the possibilities for n are; 
We can conclude that the longest codeword that could possibly be for "n" symbol is n-1 bits.