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2 years ago

Your team dives for 28 lobsters over 7 days. What is the average daily lobster catch?

Mathematics

2 answers:

sveta [45]2 years ago

8 0

It would be 4... You would take 28÷7

Olenka [21]2 years ago

5 0

Answer:

4 lobsters a day

Step-by-step explanation:

28 lobsters = 7 days

how many losters will they acquire in 1 day

so ; 28 losters * 1 day / 7 days

= 4 lobsters a day

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Evaluate (16+a)+ 6b divided by 3 when a = 2 and b = 3

yawa3891 [41]

Answer: 24

Step-by-step explanation:

Follow PEMDAS. Parentheses: 16+a, which is 18. There are no exponents so move on to multiplication. 6b. B is equal to 3, and 6x3 is 18. Next, division. 18/3 is 6. Now do addition so add together 18+6 which is 24.

4 0

2 years ago

The function f(x) is to be graphed on a coordinate plane.

gregori [183]

Answer:

f(x) is going to be on the y axis or intercept and what number it is on the line is in quotes f(x)="6"+2(1.05)^x it would be at 6 on the y axis.

5 0

1 year ago

If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

6 0

2 years ago

What is 12 divided by 1/6

TEA [102]

The answer would be, 72.

5 0

2 years ago

A + x + p + 8 = r<br> solve for x<br><br> all help is appreciated!!

Norma-Jean [14]

a+x+p+8 =r

(to solve isolate x)

x=r-(a+p+8)

x= r-a-p-8

8 0

3 years ago