Question

The frequency table below shows the antenna careers among the incoming class of first-year college students. Every student is chosen at random what is the probability that he or she intends to have a career as an engineer medical doctor or surgeon?
a. 28.7%
b. 44%
c.47%
d. 4.4%​

Answer 1

To solve this you must use a proportion like so...

$\frac{part}{whole} = \frac{part}{whole}$

The total number of students that can be chosen are 4,663. This number will represent the whole of one fraction in the proportion. We want to know what percent probability out of these students are engineer, medical doctor/surgeon. This would be considered the part of this fraction. Sum the number of engineering students (615) with medical doctors/surgeons (723) to find this number

723 + 615 = 1,338 students that want to be an engineer or medical doctor/surgeon

Percent's are always taken out of the 100. This means that the other fraction in the proportion will have 100 as the whole and x (the unknown) as the part.

Here is your proportion:

$\frac{1,338}{4,663} =\frac{x}{100}$

Now you must cross multiply

1,338*100 = 4,663*x

133,800 = 4,663x

To isolate x divide 4,663 to both sides

133,800/4,663 = 4,663x/4,663

28.7 = x

This means that there is a 28.7% of a student with the intent of becoming an engineer or a medical doctor/surgeon to be chosen at random

Hope this helped!

~Just a girl in love with Shawn Mendes

Answer 2

Step-by-step explanation:

From the given table, we see that there are 615 students vying for engineering, and 723 for medical doctor / surgeon for a total of 1338 out of a total of 4663.

So the probability of a prospective engineer or medical doctor or surgeon from the given sample is

1338 / 4663 = 28.7% (to the tenth of a percent)