3/4 = 0.75 or 75%. So you need to find 75% of 200... Simply multiply 0.75 or 3/4 by 200 and you will get your answer... (0.75)(200) = 150....
You could also realize with this problem that 3/4 of 200 is 150 because 50 goes into 200 4 times. 50 = 1/4, 100 = 2/4 = 1/2, 150 = 3/4 & 200 = 4/4 = 1.
Ew i hate these⇆∈√,×≈↓⇒∈∧⊂∴∵√²³Ф≠→Ф
Answer:
Noah
Step-by-step explanation:
Potential energy is the amount of energy that can be transfered to kinetic. This means that the higher person will have more potential energy.
Its B just took the test the answer is B
Answer:49 sec
Step-by-step explanation:
Given
Maximum speed to reach is 183.58 mi/h
Length of course is 5 mi
acceleration rate is defined by 60mi/h in 4 sec
therefore acceleration(a)


To reach a speed of 183.58mi/h with an acceleration of 
Using equation of motion
v=u+at


t=0.00339 hours
t=12.23 s reach maximum speed
To complete course it takes


t=0.01360 hour
or 