3 years ago

A rectangle with vertices L(3, –1), M(3, –8), N(8, –8), and O(8, –1) is reflected over the y-axis.

1 answer:

Katen [24]3 years ago

7 0

i dont know if you can see it

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Kruka [31]

Answer:

1.25b

Step by step explanation:

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3 years ago

lubasha [3.4K]

14/175 x 100 = 8%

answer is A. 8 (first choice)

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oksano4ka [1.4K]

1st question: 26 miles per gallon

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3 years ago

gregori [183]

Check the picture below

thus $\bf 0= -16t^2+ 96t\impliedby \textit{hits the ground}$

solve for "t"

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3 years ago

Mkey [24]

Answer:

$1.~e^{-2} \\2.~e^{\frac{7}{2}}\\3.~e^8\\4.~e^{\frac{-11}{2}}$

Step-by-step explanation:

We have to simplify the given exponential exponents.

Exponential Properties:

$e^0 =1\\e^a.e^b = e^{a+b}\\\\\displaystyle\frac{e^a}{e^b} = e^{a-b}\\\\(e^a)^b = e^{ab}\\\\e^{-a} = \frac{1}{e^a}$

Simplification takes place in the following manner:

$(e^{-3})^\frac{2}{3}\\(e^a)^b = e^{ab}\\=e^{-3\times \frac{2}{3}}\\=e^{-2}$

$(e^4)(e^{\frac{-1}{2}})\\e^a.e^b = e^{a+b}\\=e^{(4+\frac{-1}{2})} \\= e^{\frac{7}{2}}$

$(e^{-2})^{-4}\\(e^a)^b = e^{ab}\\= e^{-2\times -4}\\=e^8$

$(e^{-4})(e^{\frac{-3}{2}})\\e^a.e^b = e^{a+b}\\=e^{(-4+\frac{-3}{2})} \\= e^{\frac{-11}{2}}$

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3 years ago