Answer:
2nd graph (in the attached pics)
Step-by-step explanation:
Graphically, the <em>x-intercepts of the graph of a quadratic function are its zeroes. </em>
There can be
- no zeroes (where graph doesn't cut the x-axis at all),
- 1 zero (where graph touches the x-axis at one point only), and
- 2 zeros (where the graph cuts the x-axis at 2 points)
Looking at the figures, the 2nd graph has no real zeroes, <em>because the graph doesn't cut the x-axis at all!</em>
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So, the answer is the second graph.
Answer:
46
Step-by-step explanation:
Answer:
30 out of 40: 75%
40 out of 50: 80%
40 out of 50 is the better score
First we'll substitute
with 

Then we can separate this.

Then we'll solve this.



Then we'll plug in to find the extraneous solutions (if any)

Answer:
D. y = 4x - 6
Step-by-step explanation:
The equation that is perpendicular to the line MN should have a slope that when multiplied by the slope of line MN will result to negative one. Therefore,
Therefore,
m₁ × m₂ = -1
Using the 2 coordinates of MN let's find the slope,
(-7, 6)(5, 3)
Therefore,
m₁ = 3 - 6 / 5 - (-7) = -3 / 12 = - 1 / 4
The equation that represent a line perpendicular to the line MN is
y = 4x - 6 because the slope slope(m₂) is 4.
From our formula,
4 × - 1 / 4 = - 1
So, option D meets the requirement.