Answer:
g) 
, h) 
Step-by-step explanation:
We proceed to solve each equation by algebraic means:
g) 
1) Given
2) 
Definition of division
3) 
4) 
Associative property
5) 
/Result
h) 
1) Given
2) 
Definition of division
3) 
4) 
Factorization/Distributive property
5) ![\left(\frac{1}{3} \right)\cdot (x+4)\cdot (x+2)\cdot \left(\frac{x-4}{x-4} \right)\cdot \left[\frac{x-5}{(x-5)^{2}} \right]](https://tex.z-dn.net/?f=%5Cleft%28%5Cfrac%7B1%7D%7B3%7D%20%5Cright%29%5Ccdot%20%28x%2B4%29%5Ccdot%20%28x%2B2%29%5Ccdot%20%5Cleft%28%5Cfrac%7Bx-4%7D%7Bx-4%7D%20%5Cright%29%5Ccdot%20%5Cleft%5B%5Cfrac%7Bx-5%7D%7B%28x-5%29%5E%7B2%7D%7D%20%5Cright%5D)
Modulative and commutative properties/Associative property
6) /
/Definition of division/Result
Answer:
The answer is "
is not a perfect square".
Step-by-step explanation:
12 is not a perfect square because it is the natural number, and no other natural number would square the number 12, that's why it is not a perfect square.
If we calculate the square root of . so, it is will give 
that is not a perfect square root which can be described as follows:
is not a perfect square root.
Answer:
-5.65
Step-by-step explanation:
Basically you're solving for both variables here.
I prefer elimination method so that is what I used.
I started off by multiplying each equation in order to get one of the variables at the same value so it would be possible to cancel it out.
Multiplying the first equation by 3 gave me,
12x + 15y = 69
Then I multiplied the second equation by 4,
-12x + 28y = -56
As you can see, it's not possible to cancel out the x variable.
12x + 15y = 69
+(-12x + 28y = -56)
_____________
13y = 13
Then just solve for y which gives you -1.
After you have one variable solved simply insert it into one of the original equations to find the other variable.
4x + 5(-1) = 23
4x - 5 = 23
4x = 28
x = 7.
And there you have it! Hope this helped!
Answer:
C) 4
Step-by-step explanation:
Replace the variable a with 4 to see if it makes the equation true.
4 + (-7) + 3 = -3 +3
-3 + 3 = 0; thererfore, the number 4 is the proper solution to the equation.
