Find the value of each expression

Mathematics

2 answers:

wariber [46]3 years ago

5 0

9 + 3 - 5
9 + 3 = 12
12 - 5 = 7

ValentinkaMS [17]3 years ago

5 0

9+3=12
12-5=7
That is a answer

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Can somebody help with these three questions plz

liraira [26]

$\bf \sqrt{2}\left(3\sqrt{2}+\sqrt{18} \right)~~
\begin{cases}
18=2\cdot 3\cdot 3\\
\qquad 2\cdot 3^2
\end{cases}\implies \sqrt{2}\left(3\sqrt{2}+\sqrt{2\cdot 3^2} \right)
\\\\\\
\sqrt{2}\left(3\sqrt{2}+3\sqrt{2} \right)\implies \sqrt{2}\left(6\sqrt{2} \right)\implies 6\left(\sqrt{2}\right)^2\implies 6\cdot 2\implies \stackrel{rational}{12}$

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Step-by-step explanation:

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Read 2 more answers

Y=-4x-7 in standard form

Lapatulllka [165]

<span>Y=-4x-7 in standard form is,</span> y + 4 * x + 7 = 0

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2 years ago

HELPP!!!!!!!!!!!!!!!!

Anvisha [2.4K]

Answer:

Step-by-step explanation:

We'll take this step by step. The equation is

$8-3\sqrt[5]{x^3}=-7$

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:

$-3\sqrt[5]{x^3}=-15$

The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:

$\sqrt[5]{x^3}=5$

Let's rewrite that radical into exponential form:

$x^{\frac{3}{5}}=5$

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

$(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}$

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:

$x=\sqrt[3]{5^5}$