The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
<h3>Answer:</h3>
208 ft²
<h3>Explanation:</h3>
Generally, carpet covers the entire floor area, so the ceiling height and door area are irrelevant. The floor area is the product of its length and width.
... floor area = (16 ft)×(13 ft) = 208 ft²
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If your 3" overhang has to do with carpeting the floor, then the required area would seem to be (16.5 ft)×(13.5 ft) = 222.75 ft².
Since C only has two and although it may look like B has three terms, when the letters are joined together like that they are basically just become one big term, so your answer would be A.
