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arlik [135]
3 years ago
11

Can measurment be used with gcf

Mathematics
1 answer:
Tcecarenko [31]3 years ago
5 0
What does "gcf" stand for?
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A store had 150 laptops in the month of January. Every month, 20% of the laptops were sold and 10 new laptops were stocked in th
Softa [21]

<u>Answer-</u>

\boxed{\boxed{f(n)=0.8(f(n-1))+10,\ f(0)=150,\ \ n>0}}

<u>Solution-</u>

Here, n represents the number of months and f(n) represents the number of laptops in the store after n months.

As the store had 150 laptops in the month of January or at the beginning.

So f(0)=150

Every month, 20% of the laptops were sold and 10 new laptops were stocked in the store.

As 20% of laptops were sold, so 80% were in the store.

So, after one month total number of laptops in the store,

\Rightarrow f(1)=0.8(150)+10

\Rightarrow f(1)=0.8(f(0))+10     (\because f(0)=150)

Again after one month total number of laptops in the store,

\Rightarrow f(2)=0.8\times (0.8(150)+10)+10

\Rightarrow f(2)=0.8(f(1))+10     (\because f(1)=0.8(150)+10)

Analyzing the pattern, the recursive function f(n) will be,

f(n)=0.8(f(n-1))+10,\ f(0)=150,\ \ n>0


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Find the values of a and b such that x^2-2x+2=(x-a)^2+b
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a = 1, b = 1

Step-by-step explanation:

Expand the right side and compare the coefficients of like terms on both sides, that is

right side

(x - a)² + b ← expand factor using FOIL

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Compare to left side x² - 2x + 2

Compare the coefficients of the x- term

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1² + b = 2

1 + b = 2 ( subtract 1 from both sides )

b = 1

Thus a = 1, b = 1

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