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-Dominant- [34]
3 years ago
14

Plz plz helpI've been stuck on this since yesterday

Mathematics
2 answers:
Vanyuwa [196]3 years ago
7 0

y=ax+b

then

-9= -9a+b

0= -6a+b


a=3 and b=18


y=3x+18

Tresset [83]3 years ago
3 0

answer is attached below

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Answer:

9 feet 1 inch

Step-by-step explanation:

So, to get the answer we want to add the heights of the boxes.

2 feet, 4 inches + 2 feet 11 inches = 4 feet 15 inches. 4 feet 15 inches + 3 feet 10 inches = 7 feet and 25 inches. 25 inches is equal to 2 feet and 1 inch, so we end up with 9 feet and 1 inch as our answer.

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What is the length of the hypotenuse in the traingle shown above?
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Step-by-step explanation:

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horrorfan [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

 g(h(x)) = \sqrt[4]{x^2 + x +5} + 3

b

 h(g(x))  = \sqrt{x}  + 7\sqrt[4]{x} + 17

c

 h(h(x)) =  [x^2 + x + 5 ]^2 + x^2 + x + 10

Step-by-step explanation:

From the question we are told that

    h(x) =  x^2  + x  + 5

and  

    g(x) = \sqrt[4]{x} + 3

Considering first question

Now we are told  g(h(x))

i.e

        g(h(x)) =  [x^2 + x + 5 ]^{\frac{1}{4} } + 3

=>     g(h(x)) = \sqrt[4]{x^2 + x +5} + 3

Considering second  question

   Now we are told  h(g(x))

i.e

    h(g(x)) =  [x^{\frac{1}{4} } + 3]^2 +  x^{\frac{1}{4} } + 3 + 5

=> h(g(x)) =  x^{\frac{1}{2} } + 6x^{\frac{1}{4} } + 9+ x^{\frac{1}{4}}  + 8

=>  h(g(x))  = x^{\frac{1}{2}} + 7x^{\frac{1}{4}} + 17

=>  h(g(x))  = \sqrt{x}  + 7\sqrt[4]{x} + 17

Considering third question

         h(h(x))= [x^2 + x + 5]^2 + [x^2 + x + 5 ] +  5

=>       h(h(x)) =  [x^2 + x + 5 ]^2 + x^2 + x + 10

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Step-by-step explanation:

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