Minus 12x both sides
0=5x^2-12x+9
use quadratic formula
for 0=ax^2+bx+c
x=
given
5x^2-12x+9
a=5
b=-12
c=9
remember: i=√-1
The correct order would be:
5/64 x 3, 1/16 x 3, 3/32 x 4, 11/64 x 4, 7/16 x 3, 3/4 x 2, 3/8 x 4, 1 7/8 x 4, 2.25 x 2, 1.5 x 4, 3 3/8 x 3, 3.75 x 3
First we have to take all of the numbers and do the multiplication. It's often easiest to turn them in to decimals so that you have a common form.
3/32 x 4 = 3/8 = .375
3/4 x 2 = 3/2 = 1.5
1 7/8 x 4 = 15/4 = 3.75
2.25 x 2 = 4.5
1.5 x 4 = 6
3/8 x 4 = 3/2 = 1.5
5/64 x 3 = 5/32 = .156
3.75 x 3 = 11.25
1/16 x 3 = 3/16 = .1875
7/16 x 3 = 21/16 = 1.31
3 3/8 x 3 = 81/8 = 10.125
11/64 x 4 = 11/16 = .687
Now we can use those to put in order.
5/64 x 3 = 5/32 = .156
1/16 x 3 = 3/16 = .1875
3/32 x 4 = 3/8 = .375
11/64 x 4 = 11/16 = .687
7/16 x 3 = 21/16 = 1.31
3/4 x 2 = 3/2 = 1.5
3/8 x 4 = 3/2 = 1.5
1 7/8 x 4 = 15/4 = 3.75
2.25 x 2 = 4.5
1.5 x 4 = 6
3 3/8 x 3 = 81/8 = 10.125
3.75 x 3 = 11.25
Which if you are looking for without the extra terms, you can check the answer at the top.
Answer:
x -2y = -4
Step-by-step explanation:
The slope of the line between points C and D is ...
m = (y2 -y1)/(x2 -x1)
m = (7 -13)/(5 -2) = -6/3 = -2
The slope of the perpendicular line is the opposite reciprocal of this: -1/(-2) = 1/2. The point-slope equation of the desired line is ...
y -k = m(x -h) . . . . line with slope m through point (h, k)
y -1 = 1/2(x -(-2))
We can rearrange this to standard form.
2y -2 = x +2 . . . . . multiply by 2
-4 = x -2y . . . . . . . subtract 2y+2
x -2y = -4 . . . . . . standard form equation of the desired line
Answer:
x=1
y=-3
z=-7
Step-by-step explanation:
