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2 years ago

How many one-degree angles are in a 70° angle?

Mathematics

2 answers:

antiseptic1488 [7]2 years ago

6 0

Answer:

Step-by-step explanation:

1 times 70 = 70

Strike441 [17]2 years ago

6 0

Answer:

Step-by-step explanation:

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Change 95.61 degrees to degrees minutes seconds

Crazy boy [7]

The answer is 95° 36' 36"

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2 years ago

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Jennifer, Luis, Robert, Anna, and Tonya are figuring out how to split the check for lunch.

kramer

8 + 15 = 23

23 - 65.45 = 42.46.

The rest of the people in the group split $42 and 46 cents.

Hope this helped!!

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3 years ago

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Please help me find surface area for each. Round to the nearest tenth if needed.

Degger [83]

Answer:

168 in², 94.25 yd²

Step-by-step explanation:

I couldn't find a formula for the SA of a triangular prism so I just found the area of each surface.

The formula for SA of a cylinder is $2\pi rh+2\pi r^{2}$

All work for triangular prism is in the image

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3 years ago

Write each expression as a single power of 10

swat32

Answer:

It is

${10}^{5}$

Step-by-step explanation:

$\frac{ {10}^{4}. {10}^{5} . {10}^{6} }{ {10}^{3} . {10}^{7} } = \frac{ {10}^{(4 + 5 + 6)} }{ {10}^{(3 + 7)} } \\ \\ = \frac{ {10}^{15} }{ {10}^{10} } \\ \\ = {10}^{(15 - 10)} \\ = {10}^{5}$

3 0

2 years ago

1. (a) Solve the differential equation (x + 1)Dy/dx= xy, = given that y = 2 when x = 0. (b) Find the area between the two curves

erastova [34]

(a) The differential equation is separable, so we separate the variables and integrate:

$(x+1)\dfrac{dy}{dx} = xy \implies \dfrac{dy}y = \dfrac x{x+1} \, dx = \left(1-\dfrac1{x+1}\right) \, dx$

$\displaystyle \frac{dy}y = \int \left(1-\frac1{x+1}\right) \, dx$

$\ln|y| = x - \ln|x+1| + C$

When x = 0, we have y = 2, so we solve for the constant C :

$\ln|2| = 0 - \ln|0 + 1| + C \implies C = \ln(2)$

Then the particular solution to the DE is

$\ln|y| = x - \ln|x+1| + \ln(2)$

We can go on to solve explicitly for y in terms of x :

$e^{\ln|y|} = e^{x - \ln|x+1| + \ln(2)} \implies \boxed{y = \dfrac{2e^x}{x+1}}$

(b) The curves y = x² and y = 2x - x² intersect for

$x^2 = 2x - x^2 \implies 2x^2 - 2x = 2x (x - 1) = 0 \implies x = 0 \text{ or } x = 1$

and the bounded region is the set

$\left\{(x,y) ~:~ 0 \le x \le 1 \text{ and } x^2 \le y \le 2x - x^2\right\}$

The area of this region is

$\displaystyle \int_0^1 ((2x-x^2)-x^2) \, dx = 2 \int_0^1 (x-x^2) \, dx = 2 \left(\frac{x^2}2 - \frac{x^3}3\right)\bigg|_0^1 = 2\left(\frac12 - \frac13\right) = \boxed{\frac13}$

7 0

2 years ago

How many one-degree angles are in a 70° angle?​

How many one-degree angles are in a 70° angle?