<span>v=d/t; t=d/v
let c=rate of the current
6/(4+c)+6/(4-c)=8
(24-6c+24+6c)/(16-c²)=8
48=128 - 8c²; c=√10 miles per hour</span>
If Karen works 1 hour, she prepares 2 kg of dough.
If Karen works 2 hours, she prepares 2 kg + 2 kg of dough.
Maybe you can see where this is going.
If Karen works 3 hours, she prepares 2 kg + 2 kg + 2 kg of dough.
If Karen works h hours, she prepares 2 kg + 2 kg + ... + 2 kg of dough, where the number of instances of 2 kg is equal to h.
Early in your math career, you learned that repeated addition can be represented by multiplication. That is, when Karen works 3 hours, she prepares 3*(2 kg) of dough. It is not that big of a stretch to see that when Karen works h hours, she will prepare h*(2 kg) of dough.
Karen's output = h*(2 kg) . . . . . . an equation for finding the amount of dough
You are asked to solve this when h=5.
Karen's output = 5*(2 kg)
Karen's output = 10 kg
If she works 5 hours, Karen can prepare 10 kg of dough.
Answer:
12
Step-by-step explanation:
X - ounces of an oil blend,
y - ounces of glycerin;
1.5 · x + 1 · y = 5.50
x + y = 4
----------------------
1.5 x + y = 5.5
x + y = 4 / · ( -1 )
----------------------
1.5 x + y = 5.5
+
- x - y = - 4
---------------------
0.5 x = 1.5
x = 1.5 : 0.5
x = 3
3 + y = 4
y = 1
There are 3 ounces of an oil blend and 1 ounce of glycerin in 4 ounces of lotion.
The answer would be 212 hellos cause i think you just multiply 106 by two but i might be wrong. hope this helps
