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Alina [70]
3 years ago
7

Are there only two prime numbers that differ by 1?

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
3 0
The only two prime numbers that differ by 1 are 3 and 2 .
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When x = 3 and y = 5, by how much does the value of 3x2 – 2y exceed the value of 2x2 – 3y ?
SpyIntel [72]

Answer:

14

Step-by-step explanation:

{3x}^{2}  - 2y \\ 3 { \times 3}^{2}  - 2 \times 5 \\ 27 - 10 = 17

{2x}^{2}  - 3y \\ 2 \times  {3}^{2}  - 3 \times 5 \\ 12 - 15 =  - 3

17 - 3 = 14

7 0
2 years ago
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500+2000+45+338+2145​
Semenov [28]

Answer:

5,028

Step-by-step explanation:

7 0
3 years ago
Caroline earns $54 babysitting for 6 hours
Lady_Fox [76]
It would be $9 per hour all you have to do is divide 54 by 6 you get 9, unit rate is 1

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6 0
3 years ago
Someone help me plz!!
likoan [24]

Answer: x=15

Step-by-step explanation:

Since these are supplementary angles, we know that if we add them together we would get 180 deg. so....

(7x-10)+ (6x-5)=180

Kay so now we can combine like terms.

13x-15=180

Now we can add 15 to both sides.

13x=195

Finally Divide 13 on both sides.

X would then now equal 15.

6 0
2 years ago
Find several points that are on the graph of the function y = x^2 + 1. Plot the points in a coordinate plane.
beks73 [17]

Answer:

Below.

Step-by-step explanation:

Plot following points.

Calculate the point by plugging in values of x into x^2 + 1

for example When x = 0, y = 0^1 + 1 = 1.

So plot plot (0, 1),

Make a table of points to plot:

x   -3    -2    -1    0    1    2     3

y   10     5     2   1     2   5    10

When you plot the points you'll see the graph is U shaped.

The function is of second degree (as it contains x^2) so it wont be linear.

8 0
3 years ago
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