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jolli1 [7]
4 years ago
12

Eula needs to buy binders that cost $4 each and notebooks that cost $2 each. She has $20. The graph of the inequality 4x + 2y ≤

20, which represents the situation, is shown.
Mathematics
1 answer:
borishaifa [10]4 years ago
7 0
So, what is the question?

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Find the product<br> BRAINLIEST IF CORRECT
frutty [35]

Answer:

Undefined.

Step-by-step explanation:

The answer is undefined because in order to multiply them, they both need to have the same amount of columns and rows.

7 0
3 years ago
I will mark you brainiest if you can answer this
Cerrena [4.2K]

Answer:

i can not see the picture

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A civil engineer is analyzing the compressive strength of concrete. Compressive strength is normally distributed with σ = 31.62
AysviL [449]

Answer:

A sample size of at least 737 specimens is required.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the width M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this problem, we have that:

M = 3, \sigma = 31.62

So:

M = z*\frac{\sigma}{\sqrt{n}}

3 = 2.575*\frac{31.62}{\sqrt{n}}

3\sqrt{n} = 81.4215

\sqrt{n} = 27.1405

n = 736.60

A sample size of at least 737 specimens is required.

6 0
4 years ago
Find the sum of the first 16 terms of an arithmetic sequence where a4=7 and a7= 16. (I need the procedure y Example) please
Luden [163]

Answer:

S₁₆ = 328

Step-by-step explanation:

the nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

given a₄ = 7 and a₇ = 16 , then

a₁ + 3d = 7 → (1)

a₁ + 6d = 16 → (2)

subtract (1) from (2) term by term to eliminate a₁

0 + 3d = 9

3d = 9 ( divide both sides by 3 )

d = 3

substitute d = 3 into (1) and solve for a₁

a₁ + 3(3) = 7

a₁ + 9 = 7 ( subtract 9 from both sides )

a₁ = - 2

the sum to n terms of an arithmetic sequence is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ]

with a₁ = - 2 and d = 3 , then

S₁₆ = \frac{16}{2} [ (2 × - 2) + (15 × 3) ]

     = 8(- 4 + 45)

     = 8 × 41

     = 328

6 0
2 years ago
Can you help me in this question?
GrogVix [38]
I can’t see your upload please upload again!!
6 0
3 years ago
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