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Taya2010 [7]
2 years ago
9

I will mark you brainiest if you can answer this

Mathematics
2 answers:
inysia [295]2 years ago
4 0
Cant see the pic well sorry
Cerrena [4.2K]2 years ago
3 0

Answer:

i can not see the picture

Step-by-step explanation:

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What are the solutions of -1 <=x-3<4? help asap ​
viva [34]
I think the answer is -1=x-3<4
4 0
2 years ago
What’s the pattern of -1, -8, -27, and -64
AURORKA [14]

Hello from MrBillDoesMath!

Answer:

a(n) = (-n)^3  where n = 1,2,3,...


Discussion:

The pattern  1,8,27, 64... is immediately recognizable as the the cube of the positive integers. But this question has a minus sign appearing before  each entry, suggesting we try this:


 - 1  =  (-1)^3

 -8  = (-2)^3

-27  = (-3)^3

-64  = (-4)^3

That's what the problem statement asked for . The answer is equivalently

-1 * (n^3)


Thank you,

MrB

6 0
3 years ago
NEED HELP, ASAP! !!! 2 QUESTIONS.
Maksim231197 [3]

Answer:

1.we know the perimeter of the triangle=x-3+x+6+x=3x+3

so,answer is (b)3x+3

2.area of the triangle=1/2*b*h

=1/2*x+2*2x+6=x+2*2x+6/2=2x^2+6x+4x+12/2=2x^2+10x+12/2=2(x^2+5x+6)/2=x^2+5x+6

so,answer is(b)x^2+5x+6

8 0
2 years ago
What is the perimeter of a square which has the same area as a circle with circumfrence of 4π
Kruka [31]

Answer:

Perimeter square = 8 sqrt(pi)

Step-by-step explanation:

The perimeter of a square is 4*s

The area of a circle is Area = pi * r^2

The circumference of a circle is C = 2*pi * r

C = 4 pi

4pi = 2*pi * r

r = 2

So the area of the circle is pi * r^2 = pi * 2^2 = 4pi

The square has the same area

Area = 4*pi

Square = 4*pi

s^2 = 4*pi

s = sqrt(4*pi)

s = 2*sqrt(pi)

The perimeter = 4 * 2 * sqrt(pi)

The perimeter = 8 * sqrt(pi)

8 0
3 years ago
Kate is constructing an equilateral triangle. She has already used her straightedge to construct the line segment shown. A line
gavmur [86]
<span>Given that Kate is constructing an equilateral triangle and she has already used her straightedge to construct a line segment AB.

What Kate should do for her next step is "</span><span>Place the point of the compass on point A and draw an arc, using AB as the width for the opening of the compass".</span>
4 0
3 years ago
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