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Answer:
d. $7,032
Explanation:
The computation of the interest expense is shown below:
= Sale value of the bond × market interest rate ÷ 0.5
= $117,205 × 12% ÷ 0.5
= $117,205 × 6%
= $7,032
Simply we multiply the sale value of the bond with the market interest rate so that the accurate amount of the interest expense can come.
We divide it by 0.5 because as the number of months is 6 months and total months is 12. The six month is calculated from the January 1 to July 1
Answer:
The company's cash conversion cycle is 75 days
Explanation:
The conversion cycle is the number of days that a business takes to convert its investment in inventory into cash flowing from the purchase and sales of the business.
Conversion cycle = Payable days + Inventory in Stock days + Receivable days
where
Payable days = Purchases term = 30 days
Inventory in stock = Number of days until inventory remains unsold = 60 - 30 days = 30 days ( As payable days are already included in inventory conversion days )
Receivable days = Sales term = 15 days
Placing values in the formula
Conversion cycle = 30 days + 30 days + 15 days
Conversion Cycle = 75 days
Answer:
$6250
$5000
$5250
Explanation:
Straight line depreciation expense = (Cost of asset - Salvage value) / useful life
($212,000 - $12,000) / 8 = $25,000
The machine was used for only 3 months in the fiscal year. Thus, the depreciation expense = $25,000 x (3/12) = $6250
Activity method based on output = (output produced that year / total output of the machine) x (Cost of asset - Salvage value)
(1000 / 40,000) x ($212,000 - $12,000) = $5000
Activity method based on hours worked = (hours worked that year / total hours of the machine) x (Cost of asset - Salvage value)
($212,000 - $12,000) x (525 / 20,0000) = $5250
Answer:
Equivalent annual cost method
Explanation:
Equivalent annual cost method is a method used to choose between two projects with an unequal life span
The decision rule is to choose the product with the higher Equivalent annual cost
Equivalent annual cost method is better for making this decision because if net present value is used, the project with the higher useful life would be chosen. this does not mean it is more profitable