Well that's a handful. Let's try to rewrite this with numbers and signs, and factor out the 6x. With the 6x factored out we can eliminate the 6 from the numerator and denominator.
[tex] \frac{6 x^{3} - 18 x^{2} -12x }{-6} = \frac{6x( x^{2} -3x - 2)}{-6} = -x(x^{2} - 3x - 2)
Answer:
We can write:
x + y = -2
xy = -80
We can rewrite the first equation as x = -y - 2 and then plug that into the second equation to get (-y-2) * y = -80 → -y² - 2y = -80 → y² + 2y - 80 = 0 → (y - 8)(y + 10) = 0 → y = 8, -10. Substituting these values into the first equation we get x = -10, 8 so the answer is (x₁, y₁) = (-10, 8) or (x₂, y₂) = (8, -10).
Divide by 7.
... |-7x -3| = 3
Unfold to two equations.
... -3 = -7x -3 . . . . . the content of the absolute value is negative
... 0 = -7x . . . . . . . . add 3
... 0 = x . . . . . . . . . . divide by -7
and
... 3 = -7x -3 . . . . . . the content of the absolute value is positive
... 6 = -7x . . . . . . . . add 3
... -6/7 = x . . . . . . . . divide by -7
The solutions are ...
... x = -6/7 or x = 0
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Many graphing programs will happily tell you the locations of x- and y-intercepts, so it is convenient to rewrite the equation so its value is zero at the solution points. We can do that by subtracting the right side constant to get ...
... 7|-7x -3| -21 = 0
Answer:
Yes , the number should be even and divisible by 5 and then it can be divisible by 10 as well