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Sonbull [250]
3 years ago
15

Let g(x)= -3x and h(x) x^2+3 Find (g°h)(0)

Mathematics
1 answer:
raketka [301]3 years ago
7 0
<h3>Answer is   -9</h3>

=================================

Work Shown:

(g°h)(x) is the same as g(h(x))

So, (g°h)(0) = g(h(0))

Effectively h(x) is the input to g(x). Let's first find h(0)

h(x) = x^2+3

h(0) = 0^2+3

h(0) = 3

So g(h(x)) becomes g(h(0)) after we replace x with 0, then it updates to g(3) when we replace h(0) with 3.

Now let's find g(3)

g(x) = -3x

g(3) = -3*3

g(3) = -9

-------

alternatively, you can plug h(x) algebraically into the g(x) function

g(x) = -3x

g( h(x) ) = -3*( h(x) ) ... replace all x terms with h(x)

g( h(x) ) = -3*(x^2 + 3) ... replace h(x) on right side with x^2+3

g( h(x) ) = -3x^2 - 9

Next we can plug in x = 0

g( h(0) )  = -3(0)^2 - 9

g( h(0) ) = -9

we get the same result.

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In a triangle, the measure of the first angle is twice the measure of the second angle. The measure of the third angle is 80° mo
trasher [3.6K]

Answer:

The measure of the first angle is 50°.

Step-by-step explanation:

Let the three angles be <em>a, b, </em>and <em>c. </em>

<em />

The measure of the first angle is twice the measure of the second angle. In other words:

a=2b

The measure of the third angle is 80° more than the measure of the second angle. In other words:

c=b+80

And since the interior angles of a triangle must equal 180°:

a+b+c=180

Substitute <em>a</em> and <em>c: </em>

<em />(2b)+b+(b+80)=180<em />

Combine like terms:

4b+80=180

Subtract 80 from both sides:

4b=100

And divide both sides by four:

b=25^\circ

So, the measure of the second angle is 25°.

Since the measure of the first is twice the second, the measure of the first angle is 50°.

(And since the measure of the third is 80° than the second, the measure of the third angle is 105°.)

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2 years ago
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Answer:

= -21x + 1

Step-by-step explanation:

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