<em>Greetings from Brasil...</em>
According to the statement of the question, we can assemble the following system of equation:
X · Y = - 2 i
X + Y = 7 ii
isolating X from i and replacing in ii:
X · Y = - 2
X = - 2/Y
X + Y = 7
(- 2/Y) + Y = 7 <em>multiplying everything by Y</em>
(- 2Y/Y) + Y·Y = 7·Y
- 2 + Y² = 7X <em> rearranging everything</em>
Y² - 7X - 2 = 0 <em>2nd degree equation</em>
Δ = b² - 4·a·c
Δ = (- 7)² - 4·1·(- 2)
Δ = 49 + 8
Δ = 57
X = (- b ± √Δ)/2a
X' = (- (- 7) ± √57)/2·1
X' = (7 + √57)/2
X' = (7 - √57)/2
So, the numbers are:
<h2>
(7 + √57)/2</h2>
and
<h2>
(7 - √57)/2</h2>
Answer:
is equivalent to 
.
This is because 
The rule is, in order to add fractions, your denominators must be equivalent. In other words, you must have the same denominator for both fractions.
<em>Now what do we do? We add!</em>
This is because 4 + 1 = 5.
Your answer is .
I hope this helps!
<h2><u>
PLEASE MARK BRAINLIEST!</u></h2>
Answer:
m = 4
you can find the answer for this on m a t h w a y (without the spaces)
I hope this helps!
