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liq [111]
3 years ago
8

Simplify pleasee it’s urgent : 8f+5f-f

Mathematics
2 answers:
Arada [10]3 years ago
6 0

Answer:

12f

Step-by-step explanation:

8f+5f-f

=13f-f

=12f

Harrizon [31]3 years ago
4 0

Answer:

12f

Step-by-step explanation:

8f+5f-f

=13f-f

=12f

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WILL GIVE BRAINLIEST find the minimum value of the parabola y=x^2+42/5
Masja [62]

Answer:

Minimum value = (0, \frac{42}{5} )

  1. Set up the function in general form
  2. Determine the direction of the graph
  3. Calculate -b/2a
  4. Find the corresponding f(x) value
  5. Write your quadratic function in standard or vertex form

Please Mark Brainliest If This Helped!

5 0
1 year ago
PLSSSS HELP ME WITH THIS QUESTION!!!
AysviL [449]

Given,  

∠AOE = 30°

∠DOB = 40°

So, ∠EOD = 180 - (30+40)           [angles on a straight line]

                =  180 - 70

                =  110

∠EOD = ∠COF                             [ vertically opposite angle]

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7 0
3 years ago
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I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

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7 0
3 years ago
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lakkis [162]

Answer:

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In other words,

y = -3 x + 11

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The tangent line goes through the point of tangency (5, g(5)). g(5) = -4. Therefore, the tangent line passes through the point (5, -4).

Apply the slope-point form of the line. The equation for a line with slope <em>m</em> that goes through point (a, b) will be y - b = m(x - a). For the tangent line in this question,

  • m = 3,
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What will be the equation of this line?

6 0
2 years ago
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Answer: B
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