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3 years ago

How many radians is 144°?

Mathematics

2 answers:

aleksandrvk [35]3 years ago

4 0

Answer:

180 radians

Step-by-step explanation:

Convert from degrees to radians using the ratio

180

.4π5 radians

Vsevolod [243]3 years ago

4 0

The raidians would be 4 * Pi / 5

While your Circles are 2 / 5

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What is the slope of the line shown below?

IrinaVladis [17]

Answer:

D. 7/3

Explanation:

Y1 - Y2 / X1 - X2

9 - -5 / 6 - 0

9 + 5 / 6

14 / 6

7/3

3 0

3 years ago

17,22,36,55,61,79 what is the median

Lunna [17]

Median is the middle number. To find median, the numbers must be ordered from least to greatest. The numbers are already ordered.

$17,22,36,55,61,79$

The middle numbers are 36 and 55, with 2 numbers on each side.

a, b, c, d, e, f

Add the 2 numbers and divide by 2

$36 + 55 = 91$

Now divide by 2

$91 \div 2 = 45.5$

The median is 45.5

6 0

3 years ago

Read 2 more answers

Find the circumference of the circle to the nearest hundredth. Use 3.14 for π. Radius 21 cm.

Ierofanga [76]

Answer:

$131.95$ $cm$

Step-by-step explanation:

$C=2 \pi r$

$C=2 \pi \times 21$

$C=42\pi$

$C \approx 131.946891451$

3 0

3 years ago

7. Find x, round to nearest degree. A 15 xo 20 B.

Marizza181 [45]

Answer:37 degrees

The processed I used to solve is below. If you have an questions let me know!

8 0

3 years ago

Lola is using a one-sample t-t- test for a population mean, µμ , to test the null hypothesis, H0:µ=40 mg/dLH0:μ=40 mg/dL , again

gavmur [86]

Answer:

d. She should reject the null hypothesis because p < 0.10.

Step-by-step explanation:

We have a t statistic, so let's solve for the P-value on our calculators. (tcdf on a TI-84 calculator is 2nd->VARS->6.)

tcdf(left bound, right bound, degrees of freedom)

Our left bound is t=1.457.

Our right bound is infinity, because we're interested in the hypothesis µ>40 mg/dL. We use 999 to represent infinity in the calculator.
Our degrees of freedom is n-1 = 15-1 = 14.

tcdf(1.457,999,14) = .084

.084 < P-value of .10, so we reject the null hypothesis.

4 0

3 years ago