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3 years ago

The answer for this question

Mathematics

2 answers:

Montano1993 [528]3 years ago

8 0

Your answer is 15 hope I helped

jonny [76]3 years ago

3 0

24- (6 +3)
Always do what is in () first
So solve like this
24 - (6+3)
24- (9)
24-9
=15

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Pls help me with this question I give out 20 points

lana [24]

Answer:

55 dollars

Step-by-step explanation:

y = total cost, x = number of sessions attended

Non-members equation: y = 5x

Members equation: y = 3x + 25

y = 3(10) + 25

y = 30 + 25

y = 55 dollars

Hope this helps!

3 0

2 years ago

Read 2 more answers

A flat circular plate has the shape of the region x squared plus y squared less than or equals 1x2+y2≤1. the plate, including t

vredina [299]

You're looking for the extreme values of $x^2+3y^2+13x$ subject to the constraint $x^2+y^2\le1$ .

The target function has partial derivatives (set equal to 0)

$\dfrac{\partial(x^2+3y^2+13x)}{\partial x}=2x+13=0\implies x=-\dfrac{13}2$

$\dfrac{\partial(x^2+3y^2+13x)}{\partial y}=6y=0\implies y=0$

so there is only one critical point at $\left(-\dfrac{13}2,0\right)$ . But this point does not fall in the region $x^2+y^2\le1$ . There are no extreme values in the region of interest, so we check the boundary.

Parameterize the boundary of $x^2+y^2\le1$ by

$x=\cos u$

$y=\sin u$

with $0\le u$ . Then $t(x,y)$ can be considered a function of $u$ alone:

$t(x,y)=t(\cos u,\sin u)=T(u)$

$T(u)=\cos^2u+3\sin^2u+13\cos u$

$T(u)=3+13\cos u-2\cos^2u$

$T(u)$ has critical points where $T'(u)=0$ :

$T'(u)=-13\sin u+4\sin u\cos u=\sin u(4\cos u-13)=0$

$(1)\quad\sin u=0\implies u=0,u=\pi$

$(2)\quad4\cos u-13=0\implies\cos u=\dfrac{13}4$

but $|\cos u|\le1$ for all $u$ , so this case yields nothing important.

At these critical points, we have temperatures of

$T(0)=14$

$T(\pi)=-12$

so the plate is hottest at (1, 0) with a temperature of 14 (degrees?) and coldest at (-1, 0) with a temp of -12.

4 0

2 years ago

What is 789 times 26372

Rus_ich [418]

Answer:

20807508

Step-by-step explanation:20807508

8 0

3 years ago

Solve the triangle A=21 C=105 c=5

gregori [183]

Answer:

Granted that uppercase letters are the angles measurements and lowercase letters are the side lengths. I also was unable to round as I don't know to what decimal you need to round to.

First to find the measure of angle B, we must subtract A and C from 180

$180-21-105=54$

B=54

Next, we can use the law of sines in order to find the measures of a and b

As a reminder, The law of sines is

$\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}$

First, lets solve for b

$\frac{b}{sin54}=\frac{5}{sin105} \\\\b=\frac{(5)sin54}{sin105}\\\\b=4.187780119$

Next lets solve for a

$\frac{a}{sin21}=\frac{5}{sin105} \\\\a=\frac{(5)sin21}{sin105}\\\\a=1.85504901$

3 0

3 years ago

Which equation represents the following word sentence? Five more than three times x is twenty. 5x + 3 = 20 3x + 5 +20 3(x + 5) =

vitfil [10]

So five plus three times x equals twenty because five is alone and you’re adding three times x and is represents the equal sign and twenty is alone. So the equation is this 5 + 3x = 20

6 0

2 years ago