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Step2247 [10]
3 years ago
14

Find the missing angle measures in the given rhombus.

Mathematics
1 answer:
jeyben [28]3 years ago
3 0

Answer:

(1) = 38\°

(2) = 90\°

(3) = 90\°

(4) = 38\°

Step-by-step explanation:

The diagonals of a rhombus are perpendicular to each other, so angles (2) and (3) are equal 90°.

To find angle (1), we can use the sum of internal angles in the left triangle with angles 52°, (1), and (2):

52 + (1) + (2) = 180

(1) = 180 - 52 - 90

(1) = 38\°

The diagonals of a rhombus bisects the angles, to the angle next to the angle of 52° is also 52°, then, in the upper triangle, we have:

52 + (4) + 90 = 180

(4) = 38\°

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Answer:

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Step-by-step explanation:

We need to find out the LCM of 56 , 42 , 28 . So Lowest Common Multiple known as LCM is the lowest multiple which is divisible by all the numbers whose LCM is taken out . It can we done by two methods. Both of which are discussed in the attachment .

For complete solution kindly refer to the attachment .

<u>Related</u><u> Information</u><u> </u><u>:</u><u>-</u><u> </u>

<u>•</u><u> </u><u>HCF </u><u>:</u><u>-</u>

  • It stands for Highest Common Factor . It is the highest numbers which divides out completely the numbers without leaving remainder of the numbers whose HCF is we are finding out .

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Check the explanation

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If F(x) and 1(x) are inverse functions of each other and f(x) = 2x+5, what is (8)?
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You are to manufacture a rectangular box with 3 dimensions x, y and z, and volume v=8000. Find the dimensions which minimize the
Inga [223]

Answer:

20 by 20 by 20

Step-by-step explanation:

Let the total surface of the rectangular box be expressed as S = 2xy + 2yz + 2xz

x is the length of the box

y is the width and

z is the height of the box.

S = 2xy + 2yz + 2xz ... 1

Given the volume V = xyz = 8000 ... 2

From equation 2;

z = 8000/xy

Substituting into equation 1;

S = 2xy + 2y(8000/xy)+ 2x(8000/xy)

S = 2xy+16000/x+16000/y

Differentiating the resulting equation with respect to x and y will give;

dS/dx = 2y + (-16000x⁻²)

dS/dx = 2y - 16000/x²

Similarly,

dS/dy = 2x  + (-160000y⁻²)

dS/dy = 2x - 16000/y²

Note that at the turning point, ds/dx = 0 and ds/dy = 0, hence;

2y - 16000/x² = 0 and 2x - 16000/y² = 0

2y = 16000/x² and 2x = 16000/y²

2y = 16000/(8000/y²)²

2y = 16000×y⁴/64,000,000

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x = 20

Since Volume of the box is V = xyz

8000 = 20(20)z

8000 = 400z

z = 8000/400

z = 20

Hence, the dimensions which minimize the surface area of this box is 20 by 20 by 20.

3 0
4 years ago
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