In a rectangle, length is 6 inches more than the width. If we increase the width by 12 inches and decrease the length by 5 inche
s we arrive at a rectangle whose area is twice the area of the original rectangle. What are the dimensions of the original rectangle?
1 answer:
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Answer:
Second : 1/6 x + 47
Third : 1 2/3 x + 35 - 1 1/2 x + 12
Fourth : 5 (1/3x) + (5) (7) - (3) (1/2x) + (3) (4)
Step-by-step explanation:
I would start by expanding the expression, showing each step. Then, simplify by collecting like terms.
To expand, you multiply the term outside of the brackets by each term inside the brackets.
5(1/3x + 7) - 3(1/2x - 4)
= 5(1/3x) + (5)(7) - (3)(1/2x) + (3)(4) Showing how to expand
= 5/3x + 35 - 3/2x + 12 Simplified above step by multiplying
= 5/3x - 3/2x + 47 Collected like terms (35 + 12 = 47)
= 10/6x - 9/6x + 47 Change fractions to the common denominator 6
= + 47 Combine fractions with common denominator
= 1/6x + 47 Fully expanded
See which options match the steps I took to expand the original expression.
The second step is the same as option 4.
The last step is the same as option 2.
I bolded those steps that are the same.
Some options use mixed fractions (whole numbers and fractions).
From the third step, I will convert the improper fractions to mixed fractions.
5/3x + 35 - 3/2x + 12
= 1 2/3x + 35 - 1 1/2x + 12
This is the same as option 3.
On the left side, 5 goes into 3 ONE time. The ONE becomes the whole number. After 5 goes into 3, there is 2 left, which becomes the numerator.
On the left side, 3 goes into 2 ONE time. The ONE becomes the whole number. The remainder is 1, which becomes the numerator.