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2 years ago

15

Match each equation with a graph above:

1 answer:

Ann [662]2 years ago

7 0

Answer:

I dont know the answer but i have a hot grandson named rob. he's single and ready to mingle! #Hot #HotGrandson #AttractiveRob #HottestManInTheWholeWideWorld #ImSerious #ImForReal

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The population in the current year is 31.5 million and the real GDP is $814 million. The previous year's statistics were a popul

andrew11 [14]

Answer:

The change in the standard of living, measured by growth in real GDP per person, is 0.1356%

Step-by-step explanation:

Given,

In the current year,

Population = 31.5 million,

Real GDP = $814 million,

So, the real GDP per person = $\frac{814}{31.5}$ ≈ 25.841

In the previous year,

Population = 31 million,

Real GDP = $800 million,

So, the real GDP per person = $\frac{800}{31}$ ≈ 25.806

Hence, change percentage = $\frac{\text{Change in GDP per person}}{\text{Previous year GDP per person}}\times 100$

$=\frac{25.841-25.806}{25.806}\times 100$

$=\frac{0.035}{25.806}\times 100$

$=\frac{3.5}{25.806}$

≈ 0.1356 %

5 0

3 years ago

PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Fiesta28 [93]

<h2>For x=2</h2>

$- 10(2) + y = 4$

$- 20 + y = 4$

$y = 24$

<h2>For x=1</h2>

$- 10( 1) + y = 4$

$- 10 + y = 4$

$y = 14$

<h2>For x=0</h2>

$- 10(0) + y = 4$

$0 + y = 4$

$y = 4$

<h2>For x=-1</h2>

$- 10( - 1) + y = 4$

$10 + y = 4$

$y = - 6$

<h2>For x=2</h2>

$- 10( - 2) + y = 4$

$20 + y = 4$

$y = - 16$

8 0

2 years ago

Read 2 more answers

Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t

dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: $(x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14$

<u>Area of the big rectangle</u>: $(x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99$

The difference is: $11x+85$

$( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85$

2.

You can solve this question just by looking at the graph.

a) The height is 4 meters.

$f(d)=h=-2d^2+7d+4$

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

$f(0)=h=-2(0)^2+7(0)+4$

$h=4$

The height is 4 meters.

b) 9 meters.

For $d=1$

$f(1)=h=-2(1)^2+7(1)+4$

$f(1)=h=-2+7+4$

$h=9$

b) The ball travels 4 meters.

But to calculate it, it is when $h=0$

$0=-2d^2+7d+4$

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

3.

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

The volume of a cylinder:

$V=\pi r^2h$

$V=\pi (2.5)^2 \cdot 5$

$V=31.25 \pi$

$V_{c} \approx 98.17 \text{ m}^3$

The volume of the sphere:

$V=\frac{4}{3} \pi r^2$

$V_{s} \approx 65.4 \text{ m}^3$

The volume of the capsule is approximately $163.57 \text{ m}^3$

3 0

3 years ago

Someone please explain this to me.

stich3 [128]

Answer:

A is the answer

Step-by-step explanation:

Becuase if it has the same radius and the same height. then they will both be equal.

8 0

3 years ago

Is 270 prime ????.??

s344n2d4d5 [400]

No it is not a prime number

4 0

3 years ago

Read 2 more answers