The portion we have photographed. This is the closest. This is the span if universe that our telescopes can reach.
Answer:
Option c. ammonia and ammonia hydro-sulfide in the atmosphere
Explanation:
The color bands on Jupiter and Saturn are a result of the ammonia and ammonia hydro sulfide which condenses to form clouds in the atmosphere of the of the planets and when sunlight gets reflected from these it imparts the color to the bands of these planets.
The ammonia clouds formed in the atmosphere of these planets can be seen more clearly in Jupiter as in Saturn these bands lie at a lower altitude.
Answer:
16613 m/s
Explanation:
Given that
mass of the fly, m = 0.55 g = 0.55*10^-3 kg
Kinetic Energy of the fly, E = 7.6*10^4 J
Speed of the fly, v = ? m/s
We know that the Kinetic Energy is that energy that an object, in this case, the fly, possesses due to its motion.
The Kinetic Energy, KE of any object is represented by the formula
KE = 1/2 * m * v²
If we substitute the values in the relation, we have,
7.6*10^4 = 1/2 * 0.55*10^-3 * v²
v² = (15.2*10^4) / 0.55*10^-3
v² = 2.76*10^8
v = √2.76*10^8
v = 16613 m/s
Thus, the fly would need a speed of 16.6 km/s in order to have a Kinetic Energy of 7.6*10^4 J
Answer:
a) N = 9 Mg
, b)N_w = μ 9M
, c)
Explanation:
a) For this part we write the equations of trslacinal equilibrium
Axis y
N - Mg - 8M g = 0
N = 9 Mg
N = 9 11 9.8
N = 970.2 N
b) the force on the horizontal axis (x) som
fr -N_w = 0
fr = N_w
friction force is
fr = μ N
N_w = μ 9M
g
fr = 0.59 970.2
fr = N_w = 572,418 N
c) For this part we must use rotational equilibrium.
Στ = 0
We set a frame of reference at the bottom of the ladder and assume that the counterclockwise acceleration is positive
the weight of it is at its midpoint (L / 2)
- W L /2 cos 54 - 8M d_max cos 54+ NW L sin 54 = 0
8M d_max cos 54 = - W L / 2 cos 54 + NW L sin 54
d_max = L (-Mg 1/2 cos 54 + NW sin 54) / (8M cos 54)
d_max = L (-g / 16 + μ 9Mg / 8M tan 54)
d_max = L ( 9/8 μ g tan 54- g/16)
Answer:
x = 2.26 miles from the shore P i.e. point at which boat be landed.
Explanation:
x is the distance from point of landing i.e R and P
So, she cover a distance miles
She rows with a speed of 3 miles per hour.
So, time taken for rowing
She walks a distance = RQ = 14-x
She walks with a speed of 4 miles per hour.
So, time taken by the woman for walking \
Thus, total time taken
For total time to be least, T ' = 0
T '
x = 2.26 miles from the shore P