The amount of energy is ALWAYS conserved based on the law of conservation of energy. Therefore, the amount of energy will remain the same.
Nimbostratus clouds cause precipitation
After the great 1906 San Francisco earthquake, geolophysicistHarry Fielding Reid examined the displacement of the ground surface along the San Andreas Fault. He concluded that the quake must have been the result of the elastic reboundof the strain energy in the rocks on either side of the fault.
strain energy is 0. 5x force x (compression) X (compression)
There is a lot of force and a bit of compression when rocks squash up against other rocks causing earthquakes
Answer:
a) W₁ = 54000 Lb-ft
b) W₂ = 77760 Lb-ft
c) W₃ = 24000 Lb-ft
W₄ = 40560 Lb-ft
Step by step
W= ∫₁² ydF 1 and 2 are the levels of liquid
Where dF is the differential of weight of a thin layer
y is the height of the differential layer and
ρ*V = F
Then
dF = ρ* A*dy*g
ρ*g = 60 lb/ft³
A= Area of the base then
Area of the base is:
A(b) = 4*2 = 8 ft²
Now we have the liquid weighs 60 lb/ft³
Then the work is:
a)
W₁ = ∫₀¹⁵ 8*60*y*dy ⇒ W₁ =480* ∫₀¹⁵ y*dy
W₁ =480* y² /2 |₀¹⁵ ⇒ 480/2 [ (15)² - 0 ]
W₁ = 240*225
W₁ = 54000 Lb-ft
b) The same expression, but in this case we have to pump 3 feet higher, then:
W₂ = ∫₀¹⁸ 480*y*dy ⇒ 480*∫₀¹⁸ydy ⇒ 480* y²/2 |₀¹⁸
W₂ = 480/2 * (18)²
W₂ = 240*324
W₂ = 77760 Lb-ft
c) To pump two-thirds f the liquid we have
2/3* 15 = 10
W₃ = 480*∫₀¹⁰ y*dy ⇒ W₃ = 480* y²/2 |₀¹⁰
W₃ = 240*(10)²
W₃ = 24000 Lb-ft
d)
W₄ =480*∫₀¹³ y*dy
W₄ =480* y²/2 |₀¹³
W₄ = 240*(13)²
W₄ = 240*169
W₄ = 40560 Lb-ft
Answer:
Tangential velocity = 10.9 m/S
Explanation:
As per the data given in the question,
Force = 20 N
Time = 1.2 S
Length = 16.5 cm
Radius = 33.0 cm
Moment of inertia = 1200 kg.cm^2 = 1200 × 10^(-4) kg.m^2
= 1200 × 10^(-2) m^2
Revolution of the pedal ÷ revolution of wheel = 1
Torque on the pedal = Force × Length
= 20 × 16.5 10^(-2)
= 3.30 N m
So, Angular acceleration = Torque ÷ Moment of inertia
= 3.30 ÷ 12 × 10^(-2)
= 27.50 rad ÷ S^2
Since wheel started rotating from rest, so initial angular velocity = 0 rad/S
Now, Angular velocity = Initial angular velocity + Angular Acceleration × Time
= 0 + 27.50 × 1.2
= 33 rad/S
Hence, Tangential velocity = Angular velocity × Radius
= 33 × 33 × 10^(-2)
= 10.9 m/S
