To find an outlier, multiply the IQR by 1.5
172,500 * 1.5 = 258,750
now, u add that to Q3.....545,000 + 258,750 = 803,750....anything above this number is an outlier
now,u subtract that from Q1....372,500 - 258,750 = 113,750....anything below that is an outlier
u have already done this...u have found the higher end and the lower end....so anyting larger then the higher end or lower then the lower end is ur outlier
so in ur data, there is only 1 outlier and that is 933.....130 is not an outlier because it is not less then 113,750.
She will plant again in 2 days and trim them again in 15 days.
That would be my guess.
I don't see a mistake. You solve in parentheses first, then you solve exponents. If the exponent is 0 in this context, the answer would be 0.
The price of the small pots is $2.40 so you would have 2.4s ( multiply the number of small pots by the price)
She bought a total of 14 pots, so the number of large pots would be 14 - s ( subtract the number of small pots from the total )
Now you have:
L = 14-s
2.4s + 5.6(14-s) = 49.6
The answer is C.
