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denpristay [2]
3 years ago
10

Solve x∕4 + y∕3 = 1 for x.

Mathematics
1 answer:
VladimirAG [237]3 years ago
7 0

Answer:

D)x = 4∕3y – 4

Step-by-step explanation:

\frac{x}{4}  +  \frac{y}{3}  = 1

3x + 4y = 12

3x = 12 - 4y

x = 4 -  \frac{4}{3} y

x = 4 -  \frac{4}{3} y

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Wrtie the numbers in increasaing order, 4,-9,-5,9,-2,3
Lyrx [107]

Increasing order means from least to greatest.

-9 is the greatest negative number.

-5 is the 2nd  negative greatest number.

-2 is the least negative number.

3 is the least positive number.

4 is the second greatest positive number.

9 is the greatest positive number.

So, the answer is: -9,-5,-2,3,4,9

Hope I helped!

6 0
3 years ago
Read 2 more answers
Field book of an land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilatera
Kazeer [188]

Answer:

Total area = 237.09 cm²

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)

From the figure attached,

Area of the right triangle I = \frac{1}{2}(\text{Base})\times (\text{Height})

Area of ΔADC = \frac{1}{2}(\text{CD})(\text{AD})

                        = \frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})

                        = \frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)

                        = \frac{1}{2}(\sqrt{169-144})(12)

                        = \frac{1}{2}(5)(12)

                        = 30 cm²

Area of equilateral triangle II = \frac{\sqrt{3} }{4}(\text{Side})^2

Area of equilateral triangle II = \frac{\sqrt{3}}{4}(13)^2

                                                = \frac{(1.73)(169)}{4}

                                                = 73.0925

                                                ≈ 73.09 cm²

Area of rectangle III = Length × width

                                 = CF × CD

                                 = 7 × 5

                                 = 35 cm²

Area of trapezium EFGH = \frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})

Since, GH = GJ + JK + KH

17 = \sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}

12 = \sqrt{81-x^2}+\sqrt{225-x^2}

144 = (81 - x²) + (225 - x²) + 2\sqrt{(81-x^2)(225-x^2)}

144 - 306 = -2x² + 2\sqrt{(81-x^2)(225-x^2)}

-81 = -x² + \sqrt{(81-x^2)(225-x^2)}

(x² - 81)² = (81 - x²)(225 - x²)

x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴

144x² - 11664 = 0

x² = 81

x = 9 cm

Now area of plot IV = \frac{1}{2}(5+17)(9)

                                = 99 cm²

Total Area of the land = 30 + 73.09 + 35 + 99

                                    = 237.09 cm²

7 0
3 years ago
David is pouring an entire gallon of milk into 12 glasses. What part of a gallon will be in each glass
expeople1 [14]
This question calls for a fraction.  In a fraction, the numerator (top number) is the number of parts, while the denominator (bottom number) is the total number of parts.  One part is one glass of milk, and there are 12 parts total.  So, we get the answer 1/12.

Answer: 1/12
7 0
3 years ago
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Harold works at a men's clothing store which marks up its retail clothing by 27%
coldgirl [10]
Wheres the question?
8 0
3 years ago
The equation y=9. 5x 0. 4 represents the line of best fit for the distance (in feet) that Marcella traveled over time (in second
Bas_tet [7]

The average speed of Marcella in feet per seconds is 9.5 feet per second.

<h3>How are time taken for travel, distance traveled, and the average speed are related?</h3>

We have this below shown relation between them

\text{Average speed}  = \dfrac{\text{Distance traveled}}{\text{Total time taken to travel that distance}}\\\\or\\\\\text{Total time taken to travel that distance}= \dfrac{\text{Distance traveled}}{\text{Average speed}  }

For the given case, we have:

The equation y=9.5x  + 0.4 represents the line of best fit for the distance (in feet) that Marcella traveled over time (in seconds)

The line of best fit can be taken as approximately telling about the data points ( y = distance traveled in feet, and x = time spent )

Let the initial time be 'x' with initial distance traveled 'y', then the time after one second will be (x+1), and the distance traveled be y_1

The value of y and y_1 are calculated as:

y = 9.5x + 0.4\\y_1 = 9.5(x+1) + 0.4 = 9.5x + 9.9

Thus, the average speed is calculated at time 'x' as:

\text{Average speed}  = \dfrac{\text{Distance traveled}}{\text{Total time taken to travel that distance}}\\\\or\\\\\text{Average speed}  = \dfrac{y_1 - y}{x + 1 - x} = \dfrac{9.5x  + 9.9 - 9.5x - 0.4}{1} = 9.5 \: \rm feet/sec

We could've also used the fact that in the relation of y to x as y = mx + c, 'm' denotes the rate of y as x changes.

Thus, the average speed of Marcella in feet per seconds is 9.5 feet per second.

Learn more about average rate here:

brainly.com/question/12322912

4 0
2 years ago
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