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torisob [31]
3 years ago
11

-2c = -18 a. c= -9 b. c= -36 c. c= 9 d. c= 36

Mathematics
2 answers:
Romashka [77]3 years ago
6 0

-2c = - 18

All you need to do is divided both sides by (-2)

Now you can re-write:

-2c/-2 = -18/-2

As you know -2/-2 = 1

             and -18/-2=9

so c =9

Answer is C. c = 9

   

Marianna [84]3 years ago
4 0
All you have to do is solve for c look at the following steps :)

Step 1. Divide both sides by -2

c= \frac{-18}{-2}

Step 2. Simplify \frac{18}{-2} to - \frac{18}{2}

c= \frac{18}{2}

Step 3. Simplify \frac{18}{2} to 9

c=9

Done! :) Your answer is C. c=9
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Answer:the number is ten

Step-by-step explanation:

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Rescarchers are designing an experiment to compare two different types of running shoes, A and B, to investigate which type is b
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B.) Randomizing the type of shoe being worn by the runner ensures that we have given each runner an equal chance of selecting any type of shoe available,thereby eliminating biases which might emanate from fixing shoe type for each runner.

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Step-by-step explanation:

8 0
4 years ago
For the functions f(x) = x^2+ 8x + 2 and g(x) = -5+9, find (f•g)(x)and (f.g)(-1).
Ne4ueva [31]

Answer:  (f·g)(x) = -5x³ - 31x² + 62x + 18

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(fog)(-1) = 310

<u>Step-by-step explanation:</u>

f(x) = x² + 8x + 2          g(x) = -5x + 9

(f·g)(x) = (x² + 8x + 2)(-5x + 9)

          = -5x³ + 9x²

                    - 40x² + 72x

            <u>                    - 10x + 18</u>

          = -5x³ - 31x² + 62x + 18

(f·g)(-1)= -5(-1)³ - 31(-1)² + 62(-1) + 18

         =  -5(-1)  - 31(1)    - 62      + 18

         =    5     -   31      - 62      + 18

         =  -70

****************************************************************************************

(fog)(x) = (-5x + 9)² + 8(-5x + 9) + 2

           = 25x² - 90x + 81

                       - 40x + 72

              <u>                   +   2</u>

           = 25x² - 130x + 155

(fog)(-1) = 25(-1)² - 130(-1) + 155

            =   25    +  130    + 155

            = 310

<em>It wasn't clear if you wanted multiplication or composition so I solved both.</em>

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