Answer:
34.3
Step-by-step explanation:
no
Answer:
1. A rotation of 90°.
2. A reflection in the y-axis.
4. A translation of 3 units to the left.
Answer:
9r+13
Step-by-step explanation:
To solve this question, all we need to do is simplify the equation.
The equation is 8r+7+4+r. To simplify, we need to add like terms.
8r+r+7+4=9r+13
9r+13 is the equivalent equation to 8r+7+4+r.
Hope this helps!
Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
________________________________
now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
Answer:
x = 10
Step-by-step explanation:
it has 8 sides so:
total interior angle degrees = (180° x 8 sides) - 360° = 1080°
11x + 14 + 4x + 87 +2x + 70 + 4x + 31 + x + 92 + 3x + 167 + 5x + 48 + 2x + 251 = 1080°
combine like terms:
32x + 760° = 1080°
subtract 760° from both sides of the equation:
32x = 320°
divide both sides by 32:
x = 10
