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klio [65]
3 years ago
10

Square of the complex number (i - 2)?

Mathematics
2 answers:
Elena L [17]3 years ago
7 0
(i-2)^2=\\--------------------\\use:(a-b)^2=a^2-2ab+b^2\\--------------------\\=i^2-2\times i\times2+2^2=-1-4i+4=3-4i\\\\\\\\i=\sqrt{-1}\Rightarrow i^2=-1
scZoUnD [109]3 years ago
7 0
(i-2)^{2} = i^{2} -4i+4 \\ i= \sqrt{-1} \\ i^{2} =-1 \\  i^{2} -4i+4=-1-4i+4=-4i+3\\ answer: 3-4i
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