Answer:
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Answer:
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.
So for the book.

What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)
This is 1 subtracted by the pvalue of Z when X = 20.2. So



has a pvalue of 0.8980
1 - 0.8980 = 0.1020
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Answer:
D. 
Step-by-step explanation:
We have been given that Mikayla is a waitress who makes a guaranteed $50 per day.
Since Miklaya works 6 days per week, so the guaranteed income for one week would be
We are also told that she gets tips of 20% of all her weekly customer receipts, t. So amount earned from tips would be 20% of t, that is
.
Total amount earned in one week would be guaranteed income for 1 week plus 20% of t:

Therefore, our required function is
and option D is the correct choice.
Answer:
63 is greater than 48.1 ...
63 > 48.1
Step-by-step explanation:
63 is greater than 48 remember. So you need to remove the [.1] and focus on the 63 and 48.
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You must distribute first, so 3(8p+7r). That will equal 24p +21r. Then you must add all the values together according to like terms, so the variables must match. So simplified it will be 22+24p+30r