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3 years ago

(5x3 + 3x2 - 5x + 4)

Mathematics

1 answer:

yKpoI14uk [10]3 years ago

8 0

Hello there i hope you are having a great day :) Your question : (5x3 + 3x2 - 5x + 4) Answer : 5x^3 + 3x^2 - 5x +4

Hopefully that helps ya ❤

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John got 24 out of 25 total questions correct on his test. What percent did he score on his test?

mamaluj [8]

Answer:

24 out of 25 is equal to 96%

96% = A

Step-by-step explanation:

7 0

3 years ago

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Use Cramer's rule to find the solution to the following system of linear equations.

slavikrds [6]

Answer:

x = 53

y = 30

Step-by-step explanation:

Step(I):-

Given equations are

x -2y =-7 ...(I)

5x-9y =-5 ..(ii)

The matrix form AX = B

$\left[\begin{array}{ccc}1&-2\\ 5 & -9\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}-7\\-5\\\end{array}\right]$

The determinant

$= \left|\begin{array}{ccc}1&-2\\5&-9\\\end{array}\right| = -9+10 =1$

By using Cramer's Rule

Δ₁ = $\left[\begin{array}{ccc}-7&-2\\\\-5&-9\end{array}\right]$

The determinant is Δ₁ = -9 X -7 - (10 ) = 53

x = Δ₁ / Δ

x = 53

The determinant

Δ₂ =

Δ₂ = -5 +35

y = Δ₂/Δ = 30

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3 years ago

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Is y=9x proportinal?

igor_vitrenko [27]

Answer:

yeah it is

y is directly proportional to x

proportionality constant is 9

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3 years ago

Need help with number 1 and 2

Hatshy [7]

Me das mas información?

8 0

3 years ago

How do I do this??!.

ryzh [129]

<h3> What is trigonometry?</h3>

Trigonometry is the branch of geometry that gives the relationship between the angles and sides of a triangle.

c) proof. if cos∅ = $\frac{x}{\sqrt{x^{2} + y^{2} } }$ <em>, </em>then x = adjacent, $\sqrt{x^{2} + y^{2} }$ = hypotenuse

To solve for opposite, since it is a right angle triangle

$hypotenuse^{2}$ = $opposite^{2}$ + $adjacent^{2}$

$(\sqrt{x^{2} + y^{2} }) ^{2}$ = $opposite^{2}$ + $x^{2}$

$opposite^{2}$ = $x^{2}$ + $y^{2}$ - $x^{2}$

opposite = y

xsin∅ = x $(\frac{y}{\sqrt{x^{2} + y^{2} } })$ = $\frac{xy}{\sqrt{x^{2} } + y^{2} }$

ycos∅ = $\frac{xy}{\sqrt{x^{2} } + y^{2} }$

Therefore xsin∅ = ycos∅

d) 41 sin∅ = 40

sin∅ = 40/41

solving for adjacent = 9

tan ∅ = opp/adj = 40/9

$\frac{tan \alpha }{tan^{2}\alpha - 1 }$ = 40/9 ÷ $(\frac{40}{9} )^{2}$ - 1 = 40/9 ÷ 1600/81 - 1

= 40/9 ÷ 1519/81 = 40/9 x 81/1519 = 360/1519

e) 1 - cos ∅ = 1/2

cos ∅ = 1 - 1/2 = 1/2

∅ = cos inverse of 0.5 = 60°

tan 60 = $\sqrt{3}$ $tan^{2} 60$ = 3, sin 60 = $\frac{\sqrt{3} }{2}$ $sin^{2} 60$ = 3/4

$tan^{2} 60$ + 4 $sin^{2} 60$ = 3 + 4(3/4) = 3 + 3 = 6

Learn more about trigonometry: brainly.com/question/24349828

#SPJ1

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2 years ago